What are the solutions to the equation 4x^2+11x-3=0 ?

The solutions to the equation 4x^2+11x-3=0 are x= 1/4 ,x=-3

Find the zeros of 4x^2+11x-3=0

The zeros of 4x^2+11x-3=0 are x= 1/4 ,x=-3

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4 x^{2} + 11 x - 3 = 0

x = \frac{1}{4}, x = - 3

Solution steps

4 x^{2} + 11 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

1 1^{2} - 4 \cdot 4 (- 3) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 4}, x_{2} = \frac{- 11 - 13}{2 \cdot 4}

x = \frac{- 11 + 13}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 11 - 13}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 3

- 4 (2 x + 5) + x + 2 = - 11

6 c^{2} - 28 c + 16

4 = - \frac{2}{7} x + 2

- 2 (x + 1) \geq 12

- 3.5 = \frac{v}{0.2}

What are the solutions to the equation 4x^2+11x-3=0 ?
The solutions to the equation 4x^2+11x-3=0 are x= 1/4 ,x=-3
Find the zeros of 4x^2+11x-3=0
The zeros of 4x^2+11x-3=0 are x= 1/4 ,x=-3