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受欢迎的三角函数 >

tan^2(x)cot(x)=1

解答

tan^{2} (x) cot (x) = 1

解答

x = \frac{π}{4} + πn

+1

度数

x = 4 5^{\circ} + 18 0^{\circ} n

求解步骤

tan^{2} (x) cot (x) = 1

两边减去

1

tan^{2} (x) cot (x) - 1 = 0

使用三角恒等式改写

- 1 + cot (x) tan^{2} (x)

使用基本三角恒等式:

tan (x) = \frac{1}{cot ( x )}

= - 1 + cot (x) (\frac{1}{cot ( x )})^{2}

cot (x) (\frac{1}{cot ( x )})^{2} = \frac{1}{cot ( x )}

cot (x) (\frac{1}{cot ( x )})^{2}

(\frac{1}{cot ( x )})^{2} = \frac{1}{cot ^{2} ( x )}

(\frac{1}{cot ( x )})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cot ^{2} ( x )}

使用法则

1^{a} = 1

1^{2} = 1

= \frac{1}{cot ^{2} ( x )}

= \frac{1}{cot ^{2} ( x )} cot (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cot ( x )}{cot ^{2} ( x )}

乘以:

1 \cdot cot (x) = cot (x)

= \frac{cot ( x )}{cot ^{2} ( x )}

约分:

cot (x)

= \frac{1}{cot ( x )}

= - 1 + \frac{1}{cot ( x )}

- 1 + \frac{1}{cot ( x )} = 0

在两边乘以

cot (x)

- 1 + \frac{1}{cot ( x )} = 0

在两边乘以

cot (x)

- 1 \cdot cot (x) + \frac{1}{cot ( x )} cot (x) = 0 \cdot cot (x)

化简

- 1 \cdot cot (x) + \frac{1}{cot ( x )} cot (x) = 0 \cdot cot (x)

化简

- 1 \cdot cot (x) : - cot (x)

- 1 \cdot cot (x)

乘以:

1 \cdot cot (x) = cot (x)

= - cot (x)

化简

\frac{1}{cot ( x )} cot (x) : 1

\frac{1}{cot ( x )} cot (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cot ( x )}{cot ( x )}

约分:

cot (x)

= 1

化简

0 \cdot cot (x) : 0

0 \cdot cot (x)

使用法则

0 \cdot a = 0

= 0

- cot (x) + 1 = 0

- cot (x) + 1 = 0

- cot (x) + 1 = 0

将

1

到右边

- cot (x) + 1 = 0

两边减去

1

- cot (x) + 1 - 1 = 0 - 1

化简

- cot (x) = - 1

- cot (x) = - 1

两边除以

- 1

- cot (x) = - 1

两边除以

- 1

\frac{- cot ( x )}{- 1} = \frac{- 1}{- 1}

化简

cot (x) = 1

cot (x) = 1

验证解

找到无定义的点（奇点）:

cot (x) = 0

取

- 1 + \frac{1}{cot ( x )}

的分母，令其等于零

cot (x) = 0

以下点无定义

cot (x) = 0

将不在定义域的点与解相综合:

cot (x) = 1

cot (x) = 1

的通解

cot (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

作图

流行的例子

2sin^2(x)-cos^2(x)-4sin(x)+2=0

2 sin^{2} (x) - cos^{2} (x) - 4 sin (x) + 2 = 0

6cos^2(x)-5sin(x)+5=0

6 cos^{2} (x) - 5 sin (x) + 5 = 0

1+cos^2(a)=3sin(x)cos(x)

1 + cos^{2} (a) = 3 sin (x) cos (x)

3cos(x)+sin(x)=cos(x)-2sin(x)

3 cos (x) + sin (x) = cos (x) - 2 sin (x)

2cos(x)=cos^2(x)

2 cos (x) = cos^{2} (x)