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受欢迎的三角函数 >

4sin(2x)+2sqrt(3)=0

解答

4 sin (2 x) + 23 = 0

解答

x = \frac{2 π}{3} + πn, x = \frac{5 π}{6} + πn

+1

度数

x = 12 0^{\circ} + 18 0^{\circ} n, x = 15 0^{\circ} + 18 0^{\circ} n

求解步骤

4 sin (2 x) + 23 = 0

将

23

到右边

4 sin (2 x) + 23 = 0

两边减去

23

4 sin (2 x) + 23 - 23 = 0 - 23

化简

4 sin (2 x) = - 23

4 sin (2 x) = - 23

两边除以

4

4 sin (2 x) = - 23

两边除以

4

\frac{4 sin ( 2 x )}{4} = \frac{- 2 3}{4}

化简

\frac{4 sin ( 2 x )}{4} = \frac{- 2 3}{4}

化简

\frac{4 sin ( 2 x )}{4} : sin (2 x)

\frac{4 sin ( 2 x )}{4}

数字相除:

\frac{4}{4} = 1

= sin (2 x)

化简

\frac{- 2 3}{4} : - \frac{3}{2}

\frac{- 2 3}{4}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2 3}{4}

约分:

2

= - \frac{3}{2}

sin (2 x) = - \frac{3}{2}

sin (2 x) = - \frac{3}{2}

sin (2 x) = - \frac{3}{2}

sin (2 x) = - \frac{3}{2}

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x = \frac{4 π}{3} + 2 πn, 2 x = \frac{5 π}{3} + 2 πn

2 x = \frac{4 π}{3} + 2 πn, 2 x = \frac{5 π}{3} + 2 πn

解

2 x = \frac{4 π}{3} + 2 πn : x = \frac{2 π}{3} + πn

2 x = \frac{4 π}{3} + 2 πn

两边除以

2

2 x = \frac{4 π}{3} + 2 πn

两边除以

2

\frac{2 x}{2} = \frac{\frac{4 π}{3}}{2} + \frac{2 πn}{2}

化简

\frac{2 x}{2} = \frac{\frac{4 π}{3}}{2} + \frac{2 πn}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{4 π}{3}}{2} + \frac{2 πn}{2} : \frac{2 π}{3} + πn

\frac{\frac{4 π}{3}}{2} + \frac{2 πn}{2}

\frac{\frac{4 π}{3}}{2} = \frac{2 π}{3}

\frac{\frac{4 π}{3}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{4 π}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= \frac{4 π}{6}

约分:

2

= \frac{2 π}{3}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

数字相除:

\frac{2}{2} = 1

= πn

= \frac{2 π}{3} + πn

x = \frac{2 π}{3} + πn

x = \frac{2 π}{3} + πn

x = \frac{2 π}{3} + πn

解

2 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{6} + πn

2 x = \frac{5 π}{3} + 2 πn

两边除以

2

2 x = \frac{5 π}{3} + 2 πn

两边除以

2

\frac{2 x}{2} = \frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2}

化简

\frac{2 x}{2} = \frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2} : \frac{5 π}{6} + πn

\frac{\frac{5 π}{3}}{2} + \frac{2 πn}{2}

\frac{\frac{5 π}{3}}{2} = \frac{5 π}{6}

\frac{\frac{5 π}{3}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= \frac{5 π}{6}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

数字相除:

\frac{2}{2} = 1

= πn

= \frac{5 π}{6} + πn

x = \frac{5 π}{6} + πn

x = \frac{5 π}{6} + πn

x = \frac{5 π}{6} + πn

x = \frac{2 π}{3} + πn, x = \frac{5 π}{6} + πn

作图

流行的例子

solvefor x,3=18cos(x)

so l v e f or x, 3 = 18 cos (x)

solvefor x,2sin((pi(x-2))/6)=1

so l v e f or x, 2 sin (\frac{π ( x - 2 )}{6}) = 1

(1-sin(x))(1-sin(x))=cos^2(x)

(1 - sin (x)) (1 - sin (x)) = cos^{2} (x)

2cos(x)=cos^2(x)-1

2 cos (x) = cos^{2} (x) - 1

2sin(v)csc(v)-csc(v)=4sin(v)-2

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