zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

-4sin(8x)=0

解答

- 4 sin (8 x) = 0

解答

x = \frac{πn}{4}, x = \frac{π}{8} + \frac{πn}{4}

+1

度数

x = 0^{\circ} + 4 5^{\circ} n, x = 22. 5^{\circ} + 4 5^{\circ} n

求解步骤

- 4 sin (8 x) = 0

两边除以

- 4

- 4 sin (8 x) = 0

两边除以

- 4

\frac{- 4 sin ( 8 x )}{- 4} = \frac{0}{- 4}

化简

sin (8 x) = 0

sin (8 x) = 0

sin (8 x) = 0

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

8 x = 0 + 2 πn, 8 x = π + 2 πn

8 x = 0 + 2 πn, 8 x = π + 2 πn

解

8 x = 0 + 2 πn : x = \frac{πn}{4}

8 x = 0 + 2 πn

0 + 2 πn = 2 πn

8 x = 2 πn

两边除以

8

8 x = 2 πn

两边除以

8

\frac{8 x}{8} = \frac{2 πn}{8}

化简

x = \frac{πn}{4}

x = \frac{πn}{4}

解

8 x = π + 2 πn : x = \frac{π}{8} + \frac{πn}{4}

8 x = π + 2 πn

两边除以

8

8 x = π + 2 πn

两边除以

8

\frac{8 x}{8} = \frac{π}{8} + \frac{2 πn}{8}

化简

x = \frac{π}{8} + \frac{πn}{4}

x = \frac{π}{8} + \frac{πn}{4}

x = \frac{πn}{4}, x = \frac{π}{8} + \frac{πn}{4}

作图

流行的例子

-sin(x)+2cos(x)=0

- sin (x) + 2 cos (x) = 0

(sin(θ))/(140)=(sin(110))/(622)

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

(cosh(x))=sinh(x)

(cosh (x)) = sinh (x)

-6tan^2(θ)+4tan(θ)=-tan(θ)+1

- 6 tan^{2} (θ) + 4 tan (θ) = - tan (θ) + 1

8cos^2(x)+14cos(x)+3=0

8 cos^{2} (x) + 14 cos (x) + 3 = 0