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受欢迎的三角函数 >

(sin(θ))/(140)=(sin(110))/(622)

解答

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

解答

θ = 0.21311 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.21311 \dots + 36 0^{\circ} n

+1

弧度

θ = 0.21311 \dots + 2 πn, θ = π - 0.21311 \dots + 2 πn

求解步骤

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

在两边乘以

10

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

在两边乘以

10

\frac{sin ( θ )}{140} \cdot 10 = \frac{sin ( 11 0 ^{\circ} )}{622} \cdot 10

化简

\frac{sin ( θ )}{140} \cdot 10 = \frac{sin ( 11 0 ^{\circ} )}{622} \cdot 10

化简

\frac{sin ( θ )}{140} \cdot 10 : \frac{sin ( θ )}{14}

\frac{sin ( θ )}{140} \cdot 10

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( θ ) \cdot 10}{140}

约分:

10

= \frac{sin ( θ )}{14}

化简

\frac{sin ( 11 0 ^{\circ} )}{622} \cdot 10 : \frac{5 sin ( 11 0 ^{\circ} )}{311}

\frac{sin ( 11 0 ^{\circ} )}{622} \cdot 10

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( 11 0 ^{\circ} ) \cdot 10}{622}

约分:

2

= \frac{5 sin ( 11 0 ^{\circ} )}{311}

\frac{sin ( θ )}{14} = \frac{5 sin ( 11 0 ^{\circ} )}{311}

\frac{sin ( θ )}{14} = \frac{5 sin ( 11 0 ^{\circ} )}{311}

\frac{sin ( θ )}{14} = \frac{5 sin ( 11 0 ^{\circ} )}{311}

在两边乘以

14

\frac{sin ( θ )}{14} = \frac{5 sin ( 11 0 ^{\circ} )}{311}

在两边乘以

14

\frac{14 sin ( θ )}{14} = \frac{14 \cdot 5 sin ( 11 0 ^{\circ} )}{311}

化简

\frac{14 sin ( θ )}{14} = \frac{14 \cdot 5 sin ( 11 0 ^{\circ} )}{311}

化简

\frac{14 sin ( θ )}{14} : sin (θ)

\frac{14 sin ( θ )}{14}

数字相除:

\frac{14}{14} = 1

= sin (θ)

化简

\frac{14 \cdot 5 sin ( 11 0 ^{\circ} )}{311} : \frac{70 sin ( 11 0 ^{\circ} )}{311}

\frac{14 \cdot 5 sin ( 11 0 ^{\circ} )}{311}

数字相乘:

14 \cdot 5 = 70

= \frac{70 sin ( 11 0 ^{\circ} )}{311}

sin (θ) = \frac{70 sin ( 11 0 ^{\circ} )}{311}

sin (θ) = \frac{70 sin ( 11 0 ^{\circ} )}{311}

sin (θ) = \frac{70 sin ( 11 0 ^{\circ} )}{311}

使用反三角函数性质

sin (θ) = \frac{70 sin ( 11 0 ^{\circ} )}{311}

sin (θ) = \frac{70 sin ( 11 0 ^{\circ} )}{311}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (\frac{70 sin ( 11 0 ^{\circ} )}{311}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{70 sin ( 11 0 ^{\circ} )}{311}) + 36 0^{\circ} n

θ = arcsin (\frac{70 sin ( 11 0 ^{\circ} )}{311}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{70 sin ( 11 0 ^{\circ} )}{311}) + 36 0^{\circ} n

以小数形式表示解

θ = 0.21311 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.21311 \dots + 36 0^{\circ} n

作图

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