What is the general solution for arcsin(y)= 1/(sqrt(2)) ?

The general solution for arcsin(y)= 1/(sqrt(2)) is y=sin((sqrt(2))/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

arcsin(y)= 1/(sqrt(2))

arcsin (y) = \frac{1}{2}

y = sin (\frac{2}{2})

Solution steps

arcsin (y) = \frac{1}{2}

Simplify

\frac{1}{2} : \frac{2}{2}

\frac{1}{2}

Multiply by the conjugate

\frac{2}{2}

= \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

Apply radical rule:

a a = a

22 = 2

= 2

= \frac{2}{2}

arcsin (y) = \frac{2}{2}

Apply trig inverse properties

arcsin (y) = \frac{2}{2}

arcsin (x) = a \Rightarrow x = sin (a)

y = sin (\frac{2}{2})

y = sin (\frac{2}{2})

6 sin (y) = 0

tan (θ) = - \frac{3}{3}, 0 \leq θ \leq 2 π

cos (2 x) = sin (2 x) - 1

sinh^{2} (x) - 5 cosh (x) + 7 = 0

4 + 4 sin (x) = 0

What is the general solution for arcsin(y)= 1/(sqrt(2)) ?
The general solution for arcsin(y)= 1/(sqrt(2)) is y=sin((sqrt(2))/2)