What is the general solution for tan(x)=(60}{\frac{(-20-90))/2} ?

The general solution for tan(x)=(60}{\frac{(-20-90))/2} is x=-0.82884…+pin

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tan(x)=(60}{\frac{(-20-90))/2}

tan (x) = \frac{60}{\frac{( - 20 - 90 )}{2}}

x = - 0.82884 \dots + πn

Solution steps

tan (x) = \frac{60}{\frac{( - 20 - 90 )}{2}}

Simplify

\frac{60}{\frac{- 20 - 90}{2}} : - \frac{12}{11}

\frac{60}{\frac{- 20 - 90}{2}}

\frac{- 20 - 90}{2} = - \frac{110}{2}

\frac{- 20 - 90}{2}

Subtract the numbers:

- 20 - 90 = - 110

= \frac{- 110}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{110}{2}

= \frac{60}{- \frac{110}{2}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{60}{\frac{110}{2}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

\frac{60}{\frac{110}{2}} = \frac{60 \cdot 2}{110}

= - \frac{60 \cdot 2}{110}

Multiply the numbers:

60 \cdot 2 = 120

= - \frac{120}{110}

Cancel the common factor:

10

= - \frac{12}{11}

Apply trig inverse properties

tan (x) = - \frac{12}{11}

General solutions for

tan (x) = - \frac{12}{11}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

x = arctan (- \frac{12}{11}) + πn

x = arctan (- \frac{12}{11}) + πn

Show solutions in decimal form

x = - 0.82884 \dots + πn

0.1 \cdot sin (θ) cos (53.1 3^{\circ}) + 0.1 \cdot sin (θ) = 0

tan (θ) = (1)

sec^{2} (x) = \frac{3 3}{π}

sin (θ) (sin (θ) + 1) = 0

6 tan^{2} (x) + 13 tan (x) + 6 = 0

What is the general solution for tan(x)=(60}{\frac{(-20-90))/2} ?
The general solution for tan(x)=(60}{\frac{(-20-90))/2} is x=-0.82884…+pin