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受欢迎的三角函数 >

7sin(b)=5sin(70)

解答

7 sin (b) = 5 sin (7 0^{\circ})

解答

b = 0.73583 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.73583 \dots + 36 0^{\circ} n

+1

弧度

b = 0.73583 \dots + 2 πn, b = π - 0.73583 \dots + 2 πn

求解步骤

7 sin (b) = 5 sin (7 0^{\circ})

两边除以

7

7 sin (b) = 5 sin (7 0^{\circ})

两边除以

7

\frac{7 sin ( b )}{7} = \frac{5 sin ( 7 0 ^{\circ} )}{7}

化简

sin (b) = \frac{5 sin ( 7 0 ^{\circ} )}{7}

sin (b) = \frac{5 sin ( 7 0 ^{\circ} )}{7}

使用反三角函数性质

sin (b) = \frac{5 sin ( 7 0 ^{\circ} )}{7}

sin (b) = \frac{5 sin ( 7 0 ^{\circ} )}{7}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{5 sin ( 7 0 ^{\circ} )}{7}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{5 sin ( 7 0 ^{\circ} )}{7}) + 36 0^{\circ} n

b = arcsin (\frac{5 sin ( 7 0 ^{\circ} )}{7}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{5 sin ( 7 0 ^{\circ} )}{7}) + 36 0^{\circ} n

以小数形式表示解

b = 0.73583 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.73583 \dots + 36 0^{\circ} n

作图

流行的例子

5sin(x)+2cos^2(x)=4

5 sin (x) + 2 cos^{2} (x) = 4

cos(1/2 x)=-1,y=2

cos (\frac{1}{2} x) = - 1, y = 2

sin^2(a)=2sin^2(a)+3

sin^{2} (a) = 2 sin^{2} (a) + 3

cos(x)=(sqrt(3))/3 ,0<= x<= 2pi

cos (x) = \frac{3}{3}, 0 \leq x \leq 2 π

solvefor x,y=2sec(x)

so l v e f or x, y = 2 sec (x)