What is the general solution for tan(x)=1,-pi<x<= pi ?

The general solution for tan(x)=1,-pi<x<= pi is x= pi/4 ,x=-(3pi)/4

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tan(x)=1,-pi<x<= pi

tan (x) = 1, - π < x \leq π

x = \frac{π}{4}, x = - \frac{3 π}{4}

Degrees

x = 4 5^{\circ}, x = - 13 5^{\circ}

Solution steps

tan (x) = 1, - π < x \leq π

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solutions for the range

- π < x \leq π

x = \frac{π}{4}, x = - \frac{3 π}{4}

\frac{1}{2 cos ^{2} ( x - 1 )} = \frac{1 + tan ^{2} ( x )}{2 sec ^{2} ( x )}

sin (2 x) - 2 cos (2 x) = 0

tan (x) = \frac{87.092}{86.676}

csc (x) = - \frac{3}{2}

1 + 3 sin (θ) = 0

What is the general solution for tan(x)=1,-pi<x<= pi ?
The general solution for tan(x)=1,-pi<x<= pi is x= pi/4 ,x=-(3pi)/4