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受欢迎的三角函数 >

209cos(47)=150cos(θ)

解答

209 cos (4 7^{\circ}) = 150 cos (θ)

解答

θ = 0.31675 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 0.31675 \dots + 36 0^{\circ} n

+1

弧度

θ = 0.31675 \dots + 2 πn, θ = 2 π - 0.31675 \dots + 2 πn

求解步骤

209 cos (4 7^{\circ}) = 150 cos (θ)

交换两边

150 cos (θ) = 209 cos (4 7^{\circ})

两边除以

150

150 cos (θ) = 209 cos (4 7^{\circ})

两边除以

150

\frac{150 cos ( θ )}{150} = \frac{209 cos ( 4 7 ^{\circ} )}{150}

化简

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

使用反三角函数性质

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

cos (θ) = \frac{209 cos ( 4 7 ^{\circ} )}{150}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n

θ = arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{209 cos ( 4 7 ^{\circ} )}{150}) + 36 0^{\circ} n

以小数形式表示解

θ = 0.31675 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 0.31675 \dots + 36 0^{\circ} n

作图

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