What is the general solution for sin(X)=-1/2 ?

The general solution for sin(X)=-1/2 is X=(7pi)/6+2pin,X=(11pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(X)=-1/2

sin (X) = - \frac{1}{2}

X = \frac{7 π}{6} + 2 πn, X = \frac{11 π}{6} + 2 πn

Degrees

X = 21 0^{\circ} + 36 0^{\circ} n, X = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (X) = - \frac{1}{2}

General solutions for

sin (X) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

X = \frac{7 π}{6} + 2 πn, X = \frac{11 π}{6} + 2 πn

X = \frac{7 π}{6} + 2 πn, X = \frac{11 π}{6} + 2 πn

- 2 (sin (2 t) - cos (t)) = 0

5 cos (A) + 8 = 3 cos (A) + 6

2 + 7 cos (θ) = 4 sin^{2} (θ), - 18 0^{\circ} \leq x \leq 18 0^{\circ}

1 = 2 cos (3 θ)

cos (4 θ) + cos (2 θ) = cos (θ)

What is the general solution for sin(X)=-1/2 ?
The general solution for sin(X)=-1/2 is X=(7pi)/6+2pin,X=(11pi)/6+2pin