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شائع علم المثلثات >

sin(x+pi/3)= 1/2 cos(x-pi/6)

الحلّ

sin (x + \frac{π}{3}) = \frac{1}{2} cos (x - \frac{π}{6})

الحلّ

x = \frac{2 π}{3} + πn

درجات

x = 12 0^{\circ} + 18 0^{\circ} n

خطوات الحلّ

sin (x + \frac{π}{3}) = \frac{1}{2} cos (x - \frac{π}{6})

Rewrite using trig identities

sin (x + \frac{π}{3}) = \frac{1}{2} cos (x - \frac{π}{6})

Rewrite using trig identities

sin (x + \frac{π}{3})

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

:فعّل متطابقة الجمع لزوايا

= sin (x) cos (\frac{π}{3}) + cos (x) sin (\frac{π}{3})

sin (x) cos (\frac{π}{3}) + cos (x) sin (\frac{π}{3})

بسّط:

\frac{1}{2} sin (x) + \frac{3}{2} cos (x)

sin (x) cos (\frac{π}{3}) + cos (x) sin (\frac{π}{3})

cos (\frac{π}{3})

بسّط:

\frac{1}{2}

cos (\frac{π}{3})

استخدم المتطابقة الأساسيّة التالية:

cos (\frac{π}{3}) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= \frac{1}{2} sin (x) + sin (\frac{π}{3}) cos (x)

sin (\frac{π}{3})

بسّط:

\frac{3}{2}

sin (\frac{π}{3})

استخدم المتطابقة الأساسيّة التالية:

sin (\frac{π}{3}) = \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{1}{2} sin (x) + \frac{3}{2} cos (x)

= \frac{1}{2} sin (x) + \frac{3}{2} cos (x)

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

:فعّل متطابقة الطرح لزوايا

= cos (x) cos (\frac{π}{6}) + sin (x) sin (\frac{π}{6})

cos (x) cos (\frac{π}{6}) + sin (x) sin (\frac{π}{6})

بسّط:

\frac{3}{2} cos (x) + \frac{1}{2} sin (x)

cos (x) cos (\frac{π}{6}) + sin (x) sin (\frac{π}{6})

cos (\frac{π}{6})

بسّط:

\frac{3}{2}

cos (\frac{π}{6})

استخدم المتطابقة الأساسيّة التالية:

cos (\frac{π}{6}) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} cos (x) + sin (\frac{π}{6}) sin (x)

sin (\frac{π}{6})

بسّط:

\frac{1}{2}

sin (\frac{π}{6})

استخدم المتطابقة الأساسيّة التالية:

sin (\frac{π}{6}) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

= \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

\frac{1}{2} sin (x) + \frac{3}{2} cos (x) = \frac{1}{2} (\frac{3}{2} cos (x) + \frac{1}{2} sin (x))

\frac{1}{2} sin (x) + \frac{3}{2} cos (x) = \frac{1}{2} (\frac{3}{2} cos (x) + \frac{1}{2} sin (x))

من الطرفين

\frac{1}{2} (\frac{3}{2} cos (x) + \frac{1}{2} sin (x))

اطرح

\frac{1}{4} sin (x) + \frac{3}{4} cos (x) = 0

\frac{1}{4} sin (x) + \frac{3}{4} cos (x)

بسّط:

\frac{sin ( x ) + 3 cos ( x )}{4}

\frac{1}{4} sin (x) + \frac{3}{4} cos (x)

\frac{1}{4} sin (x) = \frac{sin ( x )}{4}

\frac{1}{4} sin (x)

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{1 \cdot sin ( x )}{4}

1 \cdot sin (x) = sin (x) :

اضرب

= \frac{sin ( x )}{4}

\frac{3}{4} cos (x) = \frac{3 cos ( x )}{4}

\frac{3}{4} cos (x)

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{3 cos ( x )}{4}

= \frac{sin ( x )}{4} + \frac{3 cos ( x )}{4}

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

فعّل القانون

= \frac{sin ( x ) + 3 cos ( x )}{4}

\frac{sin ( x ) + 3 cos ( x )}{4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sin (x) + 3 cos (x) = 0

Rewrite using trig identities

sin (x) + 3 cos (x) = 0

cos (x) \neq = 0, cos (x)

اقسم الطرفين على

\frac{sin ( x ) + 3 cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

بسّط

\frac{sin ( x )}{cos ( x )} + 3 = 0

\frac{sin ( x )}{cos ( x )} = tan (x)

:Use the basic trigonometric identity

tan (x) + 3 = 0

tan (x) + 3 = 0

انقل

3

إلى الجانب الأيمن

tan (x) + 3 = 0

من الطرفين

3

اطرح

tan (x) + 3 - 3 = 0 - 3

بسّط

tan (x) = - 3

tan (x) = - 3

tan (x) = - 3 :

حلول عامّة لـ

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{2 π}{3} + πn

x = \frac{2 π}{3} + πn

رسم

أمثلة شائعة

(2sec^2(x)-1)/(sec^2(x))=sec^2(x)

\frac{2 sec ^{2} ( x ) - 1}{sec ^{2} ( x )} = sec^{2} (x)

9(sin(x)-0.6pi)+8=0

9 (sin (x) - 0.6 π) + 8 = 0

solvefor t,v=100cos(50t+20)v

so l v e f or t, v = 100 cos (50 t + 2 0^{\circ}) v

cos(2x)=sin(pi/2-x)

cos (2 x) = sin (\frac{π}{2} - x)

sin(x)=sin(50)

sin (x) = sin (5 0^{\circ})