What is the general solution for 4-2cos(2x)=0 ?

The general solution for 4-2cos(2x)=0 is No Solution for x\in\mathbb{R}

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4-2cos(2x)=0

4 - 2 cos (2 x) = 0

No Solution for x \in R

Solution steps

4 - 2 cos (2 x) = 0

Move

4

to the right side

4 - 2 cos (2 x) = 0

Subtract

4

from both sides

4 - 2 cos (2 x) - 4 = 0 - 4

Simplify

- 2 cos (2 x) = - 4

- 2 cos (2 x) = - 4

Divide both sides by

- 2

- 2 cos (2 x) = - 4

Divide both sides by

- 2

\frac{- 2 cos ( 2 x )}{- 2} = \frac{- 4}{- 2}

Simplify

\frac{- 2 cos ( 2 x )}{- 2} = \frac{- 4}{- 2}

Simplify

\frac{- 2 cos ( 2 x )}{- 2} : cos (2 x)

\frac{- 2 cos ( 2 x )}{- 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 cos ( 2 x )}{2}

Divide the numbers:

\frac{2}{2} = 1

= cos (2 x)

Simplify

\frac{- 4}{- 2} : 2

\frac{- 4}{- 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

cos (2 x) = 2

cos (2 x) = 2

cos (2 x) = 2

- 1 \leq cos (x) \leq 1

No Solution for x \in R

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sin (2 x) tan (x) = sin (x)

What is the general solution for 4-2cos(2x)=0 ?
The general solution for 4-2cos(2x)=0 is No Solution for x\in\mathbb{R}