What is the general solution for -5-4tan(θ)=-1 ?

The general solution for -5-4tan(θ)=-1 is θ=(3pi)/4+pin

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-5-4tan(θ)=-1

- 5 - 4 tan (θ) = - 1

θ = \frac{3 π}{4} + πn

Degrees

θ = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

- 5 - 4 tan (θ) = - 1

Move

5

to the right side

- 5 - 4 tan (θ) = - 1

Add

5

to both sides

- 5 - 4 tan (θ) + 5 = - 1 + 5

Simplify

- 4 tan (θ) = 4

- 4 tan (θ) = 4

Divide both sides by

- 4

- 4 tan (θ) = 4

Divide both sides by

- 4

\frac{- 4 tan ( θ )}{- 4} = \frac{4}{- 4}

Simplify

tan (θ) = - 1

tan (θ) = - 1

General solutions for

tan (θ) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

sin (θ) = - \frac{7}{10}

10 cos (2 x) - 3 = 2

sin^{2} (θ) = 9 (cos (- θ) + 1)

sin (30 x) = 202.07

sin (x) - cos^{2} (x) = 0

What is the general solution for -5-4tan(θ)=-1 ?
The general solution for -5-4tan(θ)=-1 is θ=(3pi)/4+pin