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Beliebt Trigonometrie >

(sqrt(3))/2 =sin(arcsin(0)+c_{1})

Lösung

\frac{3}{2} = sin (arcsin (0) + c_{1})

Lösung

c_{1} = \frac{π}{3} + 2 πn, c_{1} = \frac{2 π}{3} + 2 πn

Schritte zur Lösung

\frac{3}{2} = sin (arcsin (0) + c_{1})

Tausche die Seiten

sin (arcsin (0) + c_{1}) = \frac{3}{2}

arcsin (0) = 0

arcsin (0)

Verwende die folgende triviale Identität:

arcsin (0) = 0

arcsin (0)

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= 0

= 0

sin (0 + c_{1}) = \frac{3}{2}

Allgemeine Lösung für

sin (0 + c_{1}) = \frac{3}{2}

sin (x)

Periodizitätstabelle mit

2 πn

Zyklus:

0 + c_{1} = \frac{π}{3} + 2 πn, 0 + c_{1} = \frac{2 π}{3} + 2 πn

0 + c_{1} = \frac{π}{3} + 2 πn, 0 + c_{1} = \frac{2 π}{3} + 2 πn

Löse

0 + c_{1} = \frac{π}{3} + 2 πn : c_{1} = \frac{π}{3} + 2 πn

0 + c_{1} = \frac{π}{3} + 2 πn

0 + c_{1} = c_{1}

c_{1} = \frac{π}{3} + 2 πn

Löse

0 + c_{1} = \frac{2 π}{3} + 2 πn : c_{1} = \frac{2 π}{3} + 2 πn

0 + c_{1} = \frac{2 π}{3} + 2 πn

0 + c_{1} = c_{1}

c_{1} = \frac{2 π}{3} + 2 πn

c_{1} = \frac{π}{3} + 2 πn, c_{1} = \frac{2 π}{3} + 2 πn

Graph

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