zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

tan(x-60)=-1.26,0<= x<= 360

解答

tan (x - 6 0^{\circ}) = - 1.26, 0^{\circ} \leq x \leq 36 0^{\circ}

解答

x = \frac{18 0 ^{\circ} - 3 \cdot 0.89993 \dots}{3}, x = \frac{- 3 \cdot 0.89993 \dots + 72 0 ^{\circ}}{3}

+1

弧度

x = \frac{π - 3 \cdot 0.89993 \dots}{3}, x = \frac{- 3 \cdot 0.89993 \dots + 4 π}{3}

求解步骤

tan (x - 6 0^{\circ}) = - 1.26, 0^{\circ} \leq x \leq 36 0^{\circ}

使用反三角函数性质

tan (x - 6 0^{\circ}) = - 1.26

tan (x - 6 0^{\circ}) = - 1.26

的通解

tan (x) = - a \Rightarrow x = arctan (- a) + 18 0^{\circ} n

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n

解

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n : x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n

化简

arctan (- 1.26) + 18 0^{\circ} n : - arctan (\frac{63}{50}) + 18 0^{\circ} n

arctan (- 1.26) + 18 0^{\circ} n

arctan (- 1.26) = - arctan (\frac{63}{50})

arctan (- 1.26)

= arctan (- \frac{63}{50})

利用以下特性:

arctan (- x) = - arctan (x)

arctan (- \frac{63}{50}) = - arctan (\frac{63}{50})

= - arctan (\frac{63}{50})

= - arctan (\frac{63}{50}) + 18 0^{\circ} n

x - 6 0^{\circ} = - arctan (\frac{63}{50}) + 18 0^{\circ} n

将

6 0^{\circ}

到右边

x - 6 0^{\circ} = - arctan (\frac{63}{50}) + 18 0^{\circ} n

两边加上

6 0^{\circ}

x - 6 0^{\circ} + 6 0^{\circ} = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

化简

x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

在

0 \leq x \leq 36 0^{\circ}

范围内的解

x = \frac{18 0 ^{\circ} - 3 arctan ( \frac{63}{50} )}{3}, x = \frac{- 3 arctan ( \frac{63}{50} ) + 72 0 ^{\circ}}{3}

以小数形式表示解

x = \frac{18 0 ^{\circ} - 3 \cdot 0.89993 \dots}{3}, x = \frac{- 3 \cdot 0.89993 \dots + 72 0 ^{\circ}}{3}

作图

流行的例子

0=1.5961*cos(x)+0.0422*cos(2*x)

0 = 1.5961 \cdot cos (x) + 0.0422 \cdot cos (2 \cdot x)

6 cos (7 θ) = 0

csc^2(θ)=3cot(θ)+5

csc^{2} (θ) = 3 cot (θ) + 5

sin^2(x)-2sin(x)=0,0<= x<2pi

sin^{2} (x) - 2 sin (x) = 0, 0 \leq x < 2 π

cos(2x)=((5k-8))/5

cos (2 x) = \frac{( 5 k - 8 )}{5}