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人気のある三角関数 >

tan(x-60)=-1.26,0<= x<= 360

解

tan (x - 6 0^{\circ}) = - 1.26, 0^{\circ} \leq x \leq 36 0^{\circ}

解

x = \frac{18 0 ^{\circ} - 3 \cdot 0.89993 \dots}{3}, x = \frac{- 3 \cdot 0.89993 \dots + 72 0 ^{\circ}}{3}

+1

ラジアン

x = \frac{π - 3 \cdot 0.89993 \dots}{3}, x = \frac{- 3 \cdot 0.89993 \dots + 4 π}{3}

解答ステップ

tan (x - 6 0^{\circ}) = - 1.26, 0^{\circ} \leq x \leq 36 0^{\circ}

三角関数の逆数プロパティを適用する

tan (x - 6 0^{\circ}) = - 1.26

以下の一般解

tan (x - 6 0^{\circ}) = - 1.26

tan (x) = - a \Rightarrow x = arctan (- a) + 18 0^{\circ} n

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n

解く

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n : x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

x - 6 0^{\circ} = arctan (- 1.26) + 18 0^{\circ} n

簡素化

arctan (- 1.26) + 18 0^{\circ} n : - arctan (\frac{63}{50}) + 18 0^{\circ} n

arctan (- 1.26) + 18 0^{\circ} n

arctan (- 1.26) = - arctan (\frac{63}{50})

arctan (- 1.26)

= arctan (- \frac{63}{50})

次のプロパティを使用する:

arctan (- x) = - arctan (x)

arctan (- \frac{63}{50}) = - arctan (\frac{63}{50})

= - arctan (\frac{63}{50})

= - arctan (\frac{63}{50}) + 18 0^{\circ} n

x - 6 0^{\circ} = - arctan (\frac{63}{50}) + 18 0^{\circ} n

6 0^{\circ}

を右側に移動します

x - 6 0^{\circ} = - arctan (\frac{63}{50}) + 18 0^{\circ} n

両辺に

6 0^{\circ}

を足す

x - 6 0^{\circ} + 6 0^{\circ} = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

簡素化

x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

x = - arctan (\frac{63}{50}) + 18 0^{\circ} n + 6 0^{\circ}

範囲の解答

0 \leq x \leq 36 0^{\circ}

x = \frac{18 0 ^{\circ} - 3 arctan ( \frac{63}{50} )}{3}, x = \frac{- 3 arctan ( \frac{63}{50} ) + 72 0 ^{\circ}}{3}

10進法形式で解を証明する

x = \frac{18 0 ^{\circ} - 3 \cdot 0.89993 \dots}{3}, x = \frac{- 3 \cdot 0.89993 \dots + 72 0 ^{\circ}}{3}

グラフ

人気の例

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0 = 1.5961 \cdot cos (x) + 0.0422 \cdot cos (2 \cdot x)

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