zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

sin(2x-pi/6)=0,0<= x<= 360

解答

sin (2 x - \frac{π}{6}) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

解答

x = 1 5^{\circ}, x = 10 5^{\circ}, x = 19 5^{\circ}, x = 28 5^{\circ}

+1

弧度

x = \frac{π}{12}, x = \frac{7 π}{12}, x = \frac{13 π}{12}, x = \frac{19 π}{12}

求解步骤

sin (2 x - \frac{π}{6}) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

sin (2 x - 3 0^{\circ}) = 0

的通解

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x - 3 0^{\circ} = 0 + 36 0^{\circ} n, 2 x - 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n

2 x - 3 0^{\circ} = 0 + 36 0^{\circ} n, 2 x - 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n

解

2 x - 3 0^{\circ} = 0 + 36 0^{\circ} n : x = 18 0^{\circ} n + 1 5^{\circ}

2 x - 3 0^{\circ} = 0 + 36 0^{\circ} n

0 + 36 0^{\circ} n = 36 0^{\circ} n

2 x - 3 0^{\circ} = 36 0^{\circ} n

将

3 0^{\circ}

到右边

2 x - 3 0^{\circ} = 36 0^{\circ} n

两边加上

3 0^{\circ}

2 x - 3 0^{\circ} + 3 0^{\circ} = 36 0^{\circ} n + 3 0^{\circ}

化简

2 x = 36 0^{\circ} n + 3 0^{\circ}

2 x = 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

2 x = 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

\frac{2 x}{2} = \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} = \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2} : 18 0^{\circ} n + 1 5^{\circ}

\frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{3 0 ^{\circ}}{2} = 1 5^{\circ}

\frac{3 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{6 \cdot 2}

数字相乘:

6 \cdot 2 = 12

= 1 5^{\circ}

= 18 0^{\circ} n + 1 5^{\circ}

x = 18 0^{\circ} n + 1 5^{\circ}

x = 18 0^{\circ} n + 1 5^{\circ}

x = 18 0^{\circ} n + 1 5^{\circ}

解

2 x - 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

2 x - 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n

将

3 0^{\circ}

到右边

2 x - 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n

两边加上

3 0^{\circ}

2 x - 3 0^{\circ} + 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n + 3 0^{\circ}

化简

2 x = 18 0^{\circ} + 36 0^{\circ} n + 3 0^{\circ}

2 x = 18 0^{\circ} + 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

2 x = 18 0^{\circ} + 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

\frac{2 x}{2} = 9 0^{\circ} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} = 9 0^{\circ} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

9 0^{\circ} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2} : 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

9 0^{\circ} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{3 0 ^{\circ}}{2} = 1 5^{\circ}

\frac{3 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{6 \cdot 2}

数字相乘:

6 \cdot 2 = 12

= 1 5^{\circ}

= 9 0^{\circ} + 18 0^{\circ} n + 1 5^{\circ}

对同类项分组

= 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

x = 18 0^{\circ} n + 1 5^{\circ}, x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

在

0 \leq x \leq 36 0^{\circ}

范围内的解

x = 1 5^{\circ}, x = 10 5^{\circ}, x = 19 5^{\circ}, x = 28 5^{\circ}

作图

流行的例子

(cos(x))/2 =(-sqrt(3))/2

\frac{cos ( x )}{2} = \frac{- 3}{2}

solvefor b,a=arccos((a^2-b^2-c^2)/(-2bc))

so l v e f or b, a = arccos (\frac{a ^{2} - b ^{2} - c ^{2}}{- 2 b c})

4 cos (θ) - 1 = 0

sec(y)+5tan(y)=3cos(y)

sec (y) + 5 tan (y) = 3 cos (y)

- 2 sinh (t - 2) = 0