What is the general solution for tan(θ)= 15/25 ?

The general solution for tan(θ)= 15/25 is θ=0.54041…+pin

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tan(θ)= 15/25

tan (θ) = \frac{15}{25}

θ = 0.54041 \dots + πn

Degrees

θ = 30.96375 \dots^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = \frac{15}{25}

Cancel the common factor:

5

tan (θ) = \frac{3}{5}

Apply trig inverse properties

tan (θ) = \frac{3}{5}

General solutions for

tan (θ) = \frac{3}{5}

tan (x) = a \Rightarrow x = arctan (a) + πn

θ = arctan (\frac{3}{5}) + πn

θ = arctan (\frac{3}{5}) + πn

Show solutions in decimal form

θ = 0.54041 \dots + πn

tan (φ) = 3

tan (φ) = 1

sin (x) = \frac{1}{2}, 0 \leq x \leq 2 π

2 7^{2} = 5 6^{2} + 3 5^{2} - (2 \cdot 56 \cdot 35 \cdot cos (x))

x, sin^{2} (x) - sin (x) - 2 = 0

What is the general solution for tan(θ)= 15/25 ?
The general solution for tan(θ)= 15/25 is θ=0.54041…+pin