tan(φ)=3

解答

tan (φ) = 3

φ = 1.24904 \dots + πn

度数

φ = 71.56505 \dots^{\circ} + 18 0^{\circ} n

求解步骤

tan (φ) = 3

使用反三角函数性质

tan (φ) = 3

tan (φ) = 3

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

φ = arctan (3) + πn

φ = arctan (3) + πn

以小数形式表示解

φ = 1.24904 \dots + πn

sin (x) = \frac{1}{2}, 0 \leq x \leq 2 π

2 7^{2} = 5 6^{2} + 3 5^{2} - (2 \cdot 56 \cdot 35 \cdot cos (x))

so l v e f or x, sin^{2} (x) - sin (x) - 2 = 0

cos (x - \frac{2 π}{3}) = \frac{1}{2}

cos (2 θ) + sin (θ) = 0, 0 \leq θ < 2 π