What is the general solution for sin(θ)=(10sin(105))/(24.6) ?

The general solution for sin(θ)=(10sin(105))/(24.6) is θ=0.40351…+360n,θ=180-0.40351…+360n

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sin(θ)=(10sin(105))/(24.6)

Solution

sin (θ) = \frac{10 sin ( 10 5 ^{\circ} )}{24.6}

Solution

θ = 0.40351 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.40351 \dots + 36 0^{\circ} n

Radians

θ = 0.40351 \dots + 2 πn, θ = π - 0.40351 \dots + 2 πn

Solution steps

sin (θ) = \frac{10 sin ( 10 5 ^{\circ} )}{24.6}

sin (10 5^{\circ}) = \frac{2 ( 3 + 1 )}{4}

sin (10 5^{\circ})

Rewrite using trig identities:

sin (6 0^{\circ}) cos (4 5^{\circ}) + cos (6 0^{\circ}) sin (4 5^{\circ})

sin (10 5^{\circ})

Write

sin (10 5^{\circ})

sin (6 0^{\circ} + 4 5^{\circ})

= sin (6 0^{\circ} + 4 5^{\circ})

Use the Angle Sum identity:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

= sin (6 0^{\circ}) cos (4 5^{\circ}) + cos (6 0^{\circ}) sin (4 5^{\circ})

= sin (6 0^{\circ}) cos (4 5^{\circ}) + cos (6 0^{\circ}) sin (4 5^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

Use the following trivial identity:

cos (4 5^{\circ}) = \frac{2}{2}

cos (4 5^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

Use the following trivial identity:

sin (4 5^{\circ}) = \frac{2}{2}

sin (4 5^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= \frac{3}{2} \cdot \frac{2}{2} + \frac{1}{2} \cdot \frac{2}{2}

Simplify

\frac{3}{2} \cdot \frac{2}{2} + \frac{1}{2} \cdot \frac{2}{2} : \frac{2 ( 3 + 1 )}{4}

\frac{3}{2} \cdot \frac{2}{2} + \frac{1}{2} \cdot \frac{2}{2}

Factor out common term

\frac{2}{2}

= \frac{2}{2} (\frac{3}{2} + \frac{1}{2})

\frac{3}{2} + \frac{1}{2} = \frac{3 + 1}{2}

\frac{3}{2} + \frac{1}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 + 1}{2}

= \frac{2}{2} \cdot \frac{1 + 3}{2}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 3 + 1 ) 2}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{2 ( 1 + 3 )}{4}

= \frac{2 ( 3 + 1 )}{4}

sin (θ) = \frac{10 \cdot \frac{2 ( 3 + 1 )}{4}}{24.6}

Simplify

\frac{10 \cdot \frac{2 ( 3 + 1 )}{4}}{24.6} : \frac{5 2 ( 3 + 1 )}{49.2}

\frac{10 \cdot \frac{2 ( 3 + 1 )}{4}}{24.6}

Multiply

10 \cdot \frac{2 ( 3 + 1 )}{4} : \frac{5 ( 1 + 3 )}{2}

10 \cdot \frac{2 ( 3 + 1 )}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ( 3 + 1 ) \cdot 10}{4}

Cancel the common factor:

2

= \frac{5 2 ( 1 + 3 )}{2}

Apply radical rule:

2 = 2^{\frac{1}{2}}

= \frac{5 \cdot 2 ^{\frac{1}{2}} ( 1 + 3 )}{2}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{5 ( 1 + 3 )}{2 ^{1 - \frac{1}{2}}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{5 ( 1 + 3 )}{2 ^{\frac{1}{2}}}

Apply radical rule:

2^{\frac{1}{2}} = 2

= \frac{5 ( 1 + 3 )}{2}

= \frac{\frac{5 ( 1 + 3 )}{2}}{24.6}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 ( 3 + 1 )}{2 \cdot 24.6}

Rationalize

\frac{5 ( 1 + 3 )}{2 \cdot 24.6} : \frac{5 2 ( 1 + 3 )}{49.2}

\frac{5 ( 1 + 3 )}{2 \cdot 24.6}

Multiply by the conjugate

\frac{2}{2}

= \frac{5 ( 3 + 1 ) 2}{2 \cdot 24.6 2}

2 \cdot 24.6 2 = 49.2

2 \cdot 24.6 2

Apply radical rule:

a a = a

22 = 2

= 2 \cdot 24.6

Multiply the numbers:

24.6 \cdot 2 = 49.2

= 49.2

= \frac{5 2 ( 3 + 1 )}{49.2}

= \frac{5 2 ( 1 + 3 )}{49.2}

sin (θ) = \frac{5 2 ( 3 + 1 )}{49.2}

Apply trig inverse properties

sin (θ) = \frac{5 2 ( 3 + 1 )}{49.2}

General solutions for

sin (θ) = \frac{5 2 ( 3 + 1 )}{49.2}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (\frac{5 2 ( 3 + 1 )}{49.2}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{5 2 ( 3 + 1 )}{49.2}) + 36 0^{\circ} n

θ = arcsin (\frac{5 2 ( 3 + 1 )}{49.2}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{5 2 ( 3 + 1 )}{49.2}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 0.40351 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.40351 \dots + 36 0^{\circ} n

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Frequently Asked Questions (FAQ)

What is the general solution for sin(θ)=(10sin(105))/(24.6) ?
The general solution for sin(θ)=(10sin(105))/(24.6) is θ=0.40351…+360n,θ=180-0.40351…+360n