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受欢迎的三角函数 >

cos(θ)= 3/(sqrt(11))

解答

cos (θ) = \frac{3}{11}

解答

θ = 0.44051 \dots + 2 πn, θ = 2 π - 0.44051 \dots + 2 πn

+1

弧度

θ = 0.44051 \dots + 6.28318 \dots n, θ = 5.84267 \dots + 6.28318 \dots n

求解步骤

cos (θ) = \frac{3}{11}

化简

\frac{3}{11} : \frac{3 11}{11}

\frac{3}{11}

乘以共轭根式

\frac{11}{11}

= \frac{3 11}{11 11}

1111 = 11

1111

使用根式运算法则:

a a = a

1111 = 11

= 11

= \frac{3 11}{11}

cos (θ) = \frac{3 11}{11}

使用反三角函数性质

cos (θ) = \frac{3 11}{11}

cos (θ) = \frac{3 11}{11}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3 11}{11}) + 2 πn, θ = 2 π - arccos (\frac{3 11}{11}) + 2 πn

θ = arccos (\frac{3 11}{11}) + 2 πn, θ = 2 π - arccos (\frac{3 11}{11}) + 2 πn

以小数形式表示解

θ = 0.44051 \dots + 2 πn, θ = 2 π - 0.44051 \dots + 2 πn

作图

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