解
sin(θ)−0.2cos(θ)=0.704
解
θ=2.57704…+2πn,θ=0.95933…+2πn
+1
度
θ=147.65379…∘+360∘n,θ=54.96607…∘+360∘n解答ステップ
sin(θ)−0.2cos(θ)=0.704
両辺に0.2cos(θ)を足すsin(θ)=0.704+0.2cos(θ)
両辺を2乗するsin2(θ)=(0.704+0.2cos(θ))2
両辺から(0.704+0.2cos(θ))2を引くsin2(θ)−0.495616−0.2816cos(θ)−0.04cos2(θ)=0
三角関数の公式を使用して書き換える
−0.495616+sin2(θ)−0.04cos2(θ)−0.2816cos(θ)
ピタゴラスの公式を使用する: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=−0.495616+1−cos2(θ)−0.04cos2(θ)−0.2816cos(θ)
簡素化 −0.495616+1−cos2(θ)−0.04cos2(θ)−0.2816cos(θ):−1.04cos2(θ)−0.2816cos(θ)+0.504384
−0.495616+1−cos2(θ)−0.04cos2(θ)−0.2816cos(θ)
類似した元を足す:−cos2(θ)−0.04cos2(θ)=−1.04cos2(θ)=−0.495616+1−1.04cos2(θ)−0.2816cos(θ)
数を足す/引く:−0.495616+1=0.504384=−1.04cos2(θ)−0.2816cos(θ)+0.504384
=−1.04cos2(θ)−0.2816cos(θ)+0.504384
0.504384−0.2816cos(θ)−1.04cos2(θ)=0
置換で解く
0.504384−0.2816cos(θ)−1.04cos2(θ)=0
仮定:cos(θ)=u0.504384−0.2816u−1.04u2=0
0.504384−0.2816u−1.04u2=0:u=−2.080.2816+2.177536,u=2.082.177536−0.2816
0.504384−0.2816u−1.04u2=0
標準的な形式で書く ax2+bx+c=0−1.04u2−0.2816u+0.504384=0
解くとthe二次式
−1.04u2−0.2816u+0.504384=0
二次Equationの公式:
次の場合: a=−1.04,b=−0.2816,c=0.504384u1,2=2(−1.04)−(−0.2816)±(−0.2816)2−4(−1.04)⋅0.504384
u1,2=2(−1.04)−(−0.2816)±(−0.2816)2−4(−1.04)⋅0.504384
(−0.2816)2−4(−1.04)⋅0.504384=2.177536
(−0.2816)2−4(−1.04)⋅0.504384
規則を適用 −(−a)=a=(−0.2816)2+4⋅1.04⋅0.504384
指数の規則を適用する: n が偶数であれば (−a)n=an(−0.2816)2=0.28162=0.28162+4⋅0.504384⋅1.04
数を乗じる:4⋅1.04⋅0.504384=2.09823744=0.28162+2.09823744
0.28162=0.07929856=0.07929856+2.09823744
数を足す:0.07929856+2.09823744=2.177536=2.177536
u1,2=2(−1.04)−(−0.2816)±2.177536
解を分離するu1=2(−1.04)−(−0.2816)+2.177536,u2=2(−1.04)−(−0.2816)−2.177536
u=2(−1.04)−(−0.2816)+2.177536:−2.080.2816+2.177536
2(−1.04)−(−0.2816)+2.177536
括弧を削除する: (−a)=−a,−(−a)=a=−2⋅1.040.2816+2.177536
数を乗じる:2⋅1.04=2.08=−2.080.2816+2.177536
分数の規則を適用する: −ba=−ba=−2.080.2816+2.177536
u=2(−1.04)−(−0.2816)−2.177536:2.082.177536−0.2816
2(−1.04)−(−0.2816)−2.177536
括弧を削除する: (−a)=−a,−(−a)=a=−2⋅1.040.2816−2.177536
数を乗じる:2⋅1.04=2.08=−2.080.2816−2.177536
分数の規則を適用する: −b−a=ba0.2816−2.177536=−(2.177536−0.2816)=2.082.177536−0.2816
二次equationの解:u=−2.080.2816+2.177536,u=2.082.177536−0.2816
代用を戻す u=cos(θ)cos(θ)=−2.080.2816+2.177536,cos(θ)=2.082.177536−0.2816
cos(θ)=−2.080.2816+2.177536,cos(θ)=2.082.177536−0.2816
cos(θ)=−2.080.2816+2.177536:θ=arccos(−2.080.2816+2.177536)+2πn,θ=−arccos(−2.080.2816+2.177536)+2πn
cos(θ)=−2.080.2816+2.177536
三角関数の逆数プロパティを適用する
cos(θ)=−2.080.2816+2.177536
以下の一般解 cos(θ)=−2.080.2816+2.177536cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnθ=arccos(−2.080.2816+2.177536)+2πn,θ=−arccos(−2.080.2816+2.177536)+2πn
θ=arccos(−2.080.2816+2.177536)+2πn,θ=−arccos(−2.080.2816+2.177536)+2πn
cos(θ)=2.082.177536−0.2816:θ=arccos(2.082.177536−0.2816)+2πn,θ=2π−arccos(2.082.177536−0.2816)+2πn
cos(θ)=2.082.177536−0.2816
三角関数の逆数プロパティを適用する
cos(θ)=2.082.177536−0.2816
以下の一般解 cos(θ)=2.082.177536−0.2816cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnθ=arccos(2.082.177536−0.2816)+2πn,θ=2π−arccos(2.082.177536−0.2816)+2πn
θ=arccos(2.082.177536−0.2816)+2πn,θ=2π−arccos(2.082.177536−0.2816)+2πn
すべての解を組み合わせるθ=arccos(−2.080.2816+2.177536)+2πn,θ=−arccos(−2.080.2816+2.177536)+2πn,θ=arccos(2.082.177536−0.2816)+2πn,θ=2π−arccos(2.082.177536−0.2816)+2πn
元のequationに当てはめて解を検算する
sin(θ)−0.2cos(θ)=0.704 に当てはめて解を確認する
equationに一致しないものを削除する。
解答を確認する arccos(−2.080.2816+2.177536)+2πn:真
arccos(−2.080.2816+2.177536)+2πn
挿入 n=1arccos(−2.080.2816+2.177536)+2π1
sin(θ)−0.2cos(θ)=0.704の挿入向けθ=arccos(−2.080.2816+2.177536)+2π1sin(arccos(−2.080.2816+2.177536)+2π1)−0.2cos(arccos(−2.080.2816+2.177536)+2π1)=0.704
改良0.704=0.704
⇒真
解答を確認する −arccos(−2.080.2816+2.177536)+2πn:偽
−arccos(−2.080.2816+2.177536)+2πn
挿入 n=1−arccos(−2.080.2816+2.177536)+2π1
sin(θ)−0.2cos(θ)=0.704の挿入向けθ=−arccos(−2.080.2816+2.177536)+2π1sin(−arccos(−2.080.2816+2.177536)+2π1)−0.2cos(−arccos(−2.080.2816+2.177536)+2π1)=0.704
改良−0.36606…=0.704
⇒偽
解答を確認する arccos(2.082.177536−0.2816)+2πn:真
arccos(2.082.177536−0.2816)+2πn
挿入 n=1arccos(2.082.177536−0.2816)+2π1
sin(θ)−0.2cos(θ)=0.704の挿入向けθ=arccos(2.082.177536−0.2816)+2π1sin(arccos(2.082.177536−0.2816)+2π1)−0.2cos(arccos(2.082.177536−0.2816)+2π1)=0.704
改良0.704=0.704
⇒真
解答を確認する 2π−arccos(2.082.177536−0.2816)+2πn:偽
2π−arccos(2.082.177536−0.2816)+2πn
挿入 n=12π−arccos(2.082.177536−0.2816)+2π1
sin(θ)−0.2cos(θ)=0.704の挿入向けθ=2π−arccos(2.082.177536−0.2816)+2π1sin(2π−arccos(2.082.177536−0.2816)+2π1)−0.2cos(2π−arccos(2.082.177536−0.2816)+2π1)=0.704
改良−0.93362…=0.704
⇒偽
θ=arccos(−2.080.2816+2.177536)+2πn,θ=arccos(2.082.177536−0.2816)+2πn
10進法形式で解を証明するθ=2.57704…+2πn,θ=0.95933…+2πn