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受欢迎的三角函数 >

2sin(2x+15)=1

解答

2 sin (2 x + 1 5^{\circ}) = 1

解答

x = 18 0^{\circ} n + 7. 5^{\circ}, x = 18 0^{\circ} n + 67. 5^{\circ}

+1

弧度

x = \frac{π}{24} + πn, x = \frac{3 π}{8} + πn

求解步骤

2 sin (2 x + 1 5^{\circ}) = 1

两边除以

2

2 sin (2 x + 1 5^{\circ}) = 1

两边除以

2

\frac{2 sin ( 2 x + 1 5 ^{\circ} )}{2} = \frac{1}{2}

化简

sin (2 x + 1 5^{\circ}) = \frac{1}{2}

sin (2 x + 1 5^{\circ}) = \frac{1}{2}

sin (2 x + 1 5^{\circ}) = \frac{1}{2}

的通解

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x + 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n, 2 x + 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n

2 x + 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n, 2 x + 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n

解

2 x + 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} n + 7. 5^{\circ}

2 x + 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n

将

1 5^{\circ}

到右边

2 x + 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n

两边减去

1 5^{\circ}

2 x + 1 5^{\circ} - 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ}

化简

2 x + 1 5^{\circ} - 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ}

化简

2 x + 1 5^{\circ} - 1 5^{\circ} : 2 x

2 x + 1 5^{\circ} - 1 5^{\circ}

同类项相加:

1 5^{\circ} - 1 5^{\circ} = 0

= 2 x

化简

3 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ} : 36 0^{\circ} n + 1 5^{\circ}

3 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ}

对同类项分组

= 36 0^{\circ} n + 3 0^{\circ} - 1 5^{\circ}

6, 12

的最小公倍数:

12

6, 12

最小公倍数 (LCM)

6

质因数分解:

2 \cdot 3

6

6

除以

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

都是质数，因此无法进一步因数分解

= 2 \cdot 3

12

质因数分解:

2 \cdot 2 \cdot 3

12

12

除以

212 = 6 \cdot 2

= 2 \cdot 6

6

除以

26 = 3 \cdot 2

= 2 \cdot 2 \cdot 3

2, 3

都是质数，因此无法进一步因数分解

= 2 \cdot 2 \cdot 3

将每个因子乘以它在

6

或

12

中出现的最多次数

= 2 \cdot 2 \cdot 3

数字相乘:

2 \cdot 2 \cdot 3 = 12

= 12

根据最小公倍数调整分式

将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值

12

对于

3 0^{\circ} :

将分母和分子乘以

2

3 0^{\circ} = \frac{18 0 ^{\circ} 2}{6 \cdot 2} = 3 0^{\circ}

= 3 0^{\circ} - 1 5^{\circ}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 2 - 18 0 ^{\circ}}{12}

同类项相加:

36 0^{\circ} - 18 0^{\circ} = 18 0^{\circ}

= 36 0^{\circ} n + 1 5^{\circ}

2 x = 36 0^{\circ} n + 1 5^{\circ}

2 x = 36 0^{\circ} n + 1 5^{\circ}

2 x = 36 0^{\circ} n + 1 5^{\circ}

两边除以

2

2 x = 36 0^{\circ} n + 1 5^{\circ}

两边除以

2

\frac{2 x}{2} = \frac{36 0 ^{\circ} n}{2} + \frac{1 5 ^{\circ}}{2}

化简

\frac{2 x}{2} = \frac{36 0 ^{\circ} n}{2} + \frac{1 5 ^{\circ}}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{36 0 ^{\circ} n}{2} + \frac{1 5 ^{\circ}}{2} : 18 0^{\circ} n + 7. 5^{\circ}

\frac{36 0 ^{\circ} n}{2} + \frac{1 5 ^{\circ}}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{1 5 ^{\circ}}{2} = 7. 5^{\circ}

\frac{1 5 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{12 \cdot 2}

数字相乘:

12 \cdot 2 = 24

= 7. 5^{\circ}

= 18 0^{\circ} n + 7. 5^{\circ}

x = 18 0^{\circ} n + 7. 5^{\circ}

x = 18 0^{\circ} n + 7. 5^{\circ}

x = 18 0^{\circ} n + 7. 5^{\circ}

解

2 x + 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} n + 67. 5^{\circ}

2 x + 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n

将

1 5^{\circ}

到右边

2 x + 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n

两边减去

1 5^{\circ}

2 x + 1 5^{\circ} - 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ}

化简

2 x + 1 5^{\circ} - 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ}

化简

2 x + 1 5^{\circ} - 1 5^{\circ} : 2 x

2 x + 1 5^{\circ} - 1 5^{\circ}

同类项相加:

1 5^{\circ} - 1 5^{\circ} = 0

= 2 x

化简

15 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ} : 36 0^{\circ} n + 13 5^{\circ}

15 0^{\circ} + 36 0^{\circ} n - 1 5^{\circ}

对同类项分组

= 36 0^{\circ} n + 15 0^{\circ} - 1 5^{\circ}

6, 12

的最小公倍数:

12

6, 12

最小公倍数 (LCM)

6

质因数分解:

2 \cdot 3

6

6

除以

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

都是质数，因此无法进一步因数分解

= 2 \cdot 3

12

质因数分解:

2 \cdot 2 \cdot 3

12

12

除以

212 = 6 \cdot 2

= 2 \cdot 6

6

除以

26 = 3 \cdot 2

= 2 \cdot 2 \cdot 3

2, 3

都是质数，因此无法进一步因数分解

= 2 \cdot 2 \cdot 3

将每个因子乘以它在

6

或

12

中出现的最多次数

= 2 \cdot 2 \cdot 3

数字相乘:

2 \cdot 2 \cdot 3 = 12

= 12

根据最小公倍数调整分式

将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值

12

对于

15 0^{\circ} :

将分母和分子乘以

2

15 0^{\circ} = \frac{90 0 ^{\circ} 2}{6 \cdot 2} = 15 0^{\circ}

= 15 0^{\circ} - 1 5^{\circ}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{180 0 ^{\circ} - 18 0 ^{\circ}}{12}

同类项相加:

180 0^{\circ} - 18 0^{\circ} = 162 0^{\circ}

= 13 5^{\circ}

约分:

3

= 36 0^{\circ} n + 13 5^{\circ}

2 x = 36 0^{\circ} n + 13 5^{\circ}

2 x = 36 0^{\circ} n + 13 5^{\circ}

2 x = 36 0^{\circ} n + 13 5^{\circ}

两边除以

2

2 x = 36 0^{\circ} n + 13 5^{\circ}

两边除以

2

\frac{2 x}{2} = \frac{36 0 ^{\circ} n}{2} + \frac{13 5 ^{\circ}}{2}

化简

\frac{2 x}{2} = \frac{36 0 ^{\circ} n}{2} + \frac{13 5 ^{\circ}}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{36 0 ^{\circ} n}{2} + \frac{13 5 ^{\circ}}{2} : 18 0^{\circ} n + 67. 5^{\circ}

\frac{36 0 ^{\circ} n}{2} + \frac{13 5 ^{\circ}}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{13 5 ^{\circ}}{2} = 67. 5^{\circ}

\frac{13 5 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{54 0 ^{\circ}}{4 \cdot 2}

数字相乘:

4 \cdot 2 = 8

= 67. 5^{\circ}

= 18 0^{\circ} n + 67. 5^{\circ}

x = 18 0^{\circ} n + 67. 5^{\circ}

x = 18 0^{\circ} n + 67. 5^{\circ}

x = 18 0^{\circ} n + 67. 5^{\circ}

x = 18 0^{\circ} n + 7. 5^{\circ}, x = 18 0^{\circ} n + 67. 5^{\circ}

作图

流行的例子

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16sec^2(θ)-1=0

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