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Popular >

1+2cos(60)

Solution

1 + 2 cos (6 0^{\circ})

Solution

2

Solution steps

1 + 2 cos (6 0^{\circ})

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= 1 + 2 \cdot \frac{1}{2}

Simplify

1 + 2 \cdot \frac{1}{2} : 2

1 + 2 \cdot \frac{1}{2}

2 \cdot \frac{1}{2} = 1

2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 1 + 1

Add the numbers:

1 + 1 = 2

= 2

= 2

Popular Examples

sin((6pi)/(12))

sin (\frac{6 π}{12})

5 \cdot sin (2 0^{\circ})

arctan(2.90696E20)

arctan (2.90696 E 20)

cos(pi/2)-sin((5pi)/3)+tan((9pi)/4)-cos((5pi)/6)+tan((7pi)/6)

cos (\frac{π}{2}) - sin (\frac{5 π}{3}) + tan (\frac{9 π}{4}) - cos (\frac{5 π}{6}) + tan (\frac{7 π}{6})

1/2 sin(2*pi/4)

\frac{1}{2} sin (2 \cdot \frac{π}{4})

Frequently Asked Questions (FAQ)

What is the value of 1+2cos(60) ?
The value of 1+2cos(60) is 2