What is the value of sin((6pi)/(12)) ?

The value of sin((6pi)/(12)) is 1

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sin((6pi)/(12))

sin (\frac{6 π}{12})

1

Solution steps

sin (\frac{6 π}{12})

Simplify:

\frac{6 π}{12} = \frac{π}{2}

\frac{6 π}{12}

Cancel the common factor:

6

= \frac{π}{2}

= sin (\frac{π}{2})

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1

5 \cdot sin (2 0^{\circ})

arctan (2.90696 E 20)

cos (\frac{π}{2}) - sin (\frac{5 π}{3}) + tan (\frac{9 π}{4}) - cos (\frac{5 π}{6}) + tan (\frac{7 π}{6})

\frac{1}{2} sin (2 \cdot \frac{π}{4})

arccos (cos (\frac{- π}{6}))