解答
4sin(2x−0.4)−5cos(2x−0.4)=0
解答
x=21.29605…+2πn
+1
度数
x=37.12925…∘+90∘n求解步骤
4sin(2x−0.4)−5cos(2x−0.4)=0
使用三角恒等式改写
4sin(2x−0.4)−5cos(2x−0.4)=0
使用三角恒等式改写
sin(2x−0.4)
使用角差恒等式: sin(s−t)=sin(s)cos(t)−cos(s)sin(t)=sin(2x)cos(0.4)−cos(2x)sin(0.4)
化简 sin(2x)cos(0.4)−cos(2x)sin(0.4):0.92106…sin(2x)−0.38941…cos(2x)
sin(2x)cos(0.4)−cos(2x)sin(0.4)
化简 cos(0.4):0.92106…
cos(0.4)
cos(0.4)=0.92106…=0.92106…
=0.92106…sin(2x)−sin(0.4)cos(2x)
化简 sin(0.4):0.38941…
sin(0.4)
sin(0.4)=0.38941…=0.38941…
=0.92106…sin(2x)−0.38941…cos(2x)
=0.92106…sin(2x)−0.38941…cos(2x)
使用角差恒等式: cos(s−t)=cos(s)cos(t)+sin(s)sin(t)=cos(2x)cos(0.4)+sin(2x)sin(0.4)
化简 cos(2x)cos(0.4)+sin(2x)sin(0.4):0.92106…cos(2x)+0.38941…sin(2x)
cos(2x)cos(0.4)+sin(2x)sin(0.4)
化简 cos(0.4):0.92106…
cos(0.4)
cos(0.4)=0.92106…=0.92106…
=0.92106…cos(2x)+sin(0.4)sin(2x)
化简 sin(0.4):0.38941…
sin(0.4)
sin(0.4)=0.38941…=0.38941…
=0.92106…cos(2x)+0.38941…sin(2x)
=0.92106…cos(2x)+0.38941…sin(2x)
4(0.92106…sin(2x)−0.38941…cos(2x))−5(0.92106…cos(2x)+0.38941…sin(2x))=0
化简 4(0.92106…sin(2x)−0.38941…cos(2x))−5(0.92106…cos(2x)+0.38941…sin(2x)):1.73715…sin(2x)−6.16297…cos(2x)
4(0.92106…sin(2x)−0.38941…cos(2x))−5(0.92106…cos(2x)+0.38941…sin(2x))
乘开 4(0.92106…sin(2x)−0.38941…cos(2x)):3.68424…sin(2x)−1.55767…cos(2x)
4(0.92106…sin(2x)−0.38941…cos(2x))
使用分配律: a(b−c)=ab−aca=4,b=0.92106…sin(2x),c=0.38941…cos(2x)=4⋅0.92106…sin(2x)−4⋅0.38941…cos(2x)
化简 4⋅0.92106…sin(2x)−4⋅0.38941…cos(2x):3.68424…sin(2x)−1.55767…cos(2x)
4⋅0.92106…sin(2x)−4⋅0.38941…cos(2x)
数字相乘:4⋅0.92106…=3.68424…=3.68424…sin(2x)−4⋅0.38941…cos(2x)
数字相乘:4⋅0.38941…=1.55767…=3.68424…sin(2x)−1.55767…cos(2x)
=3.68424…sin(2x)−1.55767…cos(2x)
=3.68424…sin(2x)−1.55767…cos(2x)−5(0.92106…cos(2x)+0.38941…sin(2x))
乘开 −5(0.92106…cos(2x)+0.38941…sin(2x)):−4.60530…cos(2x)−1.94709…sin(2x)
−5(0.92106…cos(2x)+0.38941…sin(2x))
使用分配律: a(b+c)=ab+aca=−5,b=0.92106…cos(2x),c=0.38941…sin(2x)=−5⋅0.92106…cos(2x)+(−5)⋅0.38941…sin(2x)
使用加减运算法则+(−a)=−a=−5⋅0.92106…cos(2x)−5⋅0.38941…sin(2x)
化简 −5⋅0.92106…cos(2x)−5⋅0.38941…sin(2x):−4.60530…cos(2x)−1.94709…sin(2x)
−5⋅0.92106…cos(2x)−5⋅0.38941…sin(2x)
数字相乘:5⋅0.92106…=4.60530…=−4.60530…cos(2x)−5⋅0.38941…sin(2x)
数字相乘:5⋅0.38941…=1.94709…=−4.60530…cos(2x)−1.94709…sin(2x)
=−4.60530…cos(2x)−1.94709…sin(2x)
=3.68424…sin(2x)−1.55767…cos(2x)−4.60530…cos(2x)−1.94709…sin(2x)
化简 3.68424…sin(2x)−1.55767…cos(2x)−4.60530…cos(2x)−1.94709…sin(2x):1.73715…sin(2x)−6.16297…cos(2x)
3.68424…sin(2x)−1.55767…cos(2x)−4.60530…cos(2x)−1.94709…sin(2x)
同类项相加:−1.55767…cos(2x)−4.60530…cos(2x)=−6.16297…cos(2x)=3.68424…sin(2x)−6.16297…cos(2x)−1.94709…sin(2x)
同类项相加:3.68424…sin(2x)−1.94709…sin(2x)=1.73715…sin(2x)=1.73715…sin(2x)−6.16297…cos(2x)
=1.73715…sin(2x)−6.16297…cos(2x)
1.73715…sin(2x)−6.16297…cos(2x)=0
在两边除以 cos(2x),cos(2x)=0cos(2x)1.73715…sin(2x)−6.16297…cos(2x)=cos(2x)0
化简cos(2x)1.73715…sin(2x)−6.16297…=0
使用基本三角恒等式: cos(x)sin(x)=tan(x)1.73715…tan(2x)−6.16297…=0
1.73715…tan(2x)−6.16297…=0
将 6.16297…到右边
1.73715…tan(2x)−6.16297…=0
两边加上 6.16297…1.73715…tan(2x)−6.16297…+6.16297…=0+6.16297…
化简1.73715…tan(2x)=6.16297…
1.73715…tan(2x)=6.16297…
两边除以 1.73715…
1.73715…tan(2x)=6.16297…
两边除以 1.73715…1.73715…1.73715…tan(2x)=1.73715…6.16297…
化简tan(2x)=3.54774…
tan(2x)=3.54774…
使用反三角函数性质
tan(2x)=3.54774…
tan(2x)=3.54774…的通解tan(x)=a⇒x=arctan(a)+πn2x=arctan(3.54774…)+πn
2x=arctan(3.54774…)+πn
解 2x=arctan(3.54774…)+πn:x=2arctan(3.54774…)+2πn
2x=arctan(3.54774…)+πn
两边除以 2
2x=arctan(3.54774…)+πn
两边除以 222x=2arctan(3.54774…)+2πn
化简x=2arctan(3.54774…)+2πn
x=2arctan(3.54774…)+2πn
x=2arctan(3.54774…)+2πn
以小数形式表示解x=21.29605…+2πn