What is the general solution for cos(x)=0.12 ?

The general solution for cos(x)=0.12 is x=1.45050…+2pin,x=2pi-1.45050…+2pin

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cos(x)=0.12

cos (x) = 0.12

x = 1.45050 \dots + 2 πn, x = 2 π - 1.45050 \dots + 2 πn

Degrees

x = 83.10789 \dots^{\circ} + 36 0^{\circ} n, x = 276.89210 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = 0.12

Apply trig inverse properties

cos (x) = 0.12

General solutions for

cos (x) = 0.12

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (0.12) + 2 πn, x = 2 π - arccos (0.12) + 2 πn

x = arccos (0.12) + 2 πn, x = 2 π - arccos (0.12) + 2 πn

Show solutions in decimal form

x = 1.45050 \dots + 2 πn, x = 2 π - 1.45050 \dots + 2 πn

0 = cos (3 θ)

6 sin (θ) + 6 = 0

cosh (z) = - 2

tan (\frac{θ}{2} + \frac{π}{3}) = - 1, 0 \leq θ < 2 π

- 9 cos^{2} (θ) + 13 = 20 sin (θ)

What is the general solution for cos(x)=0.12 ?
The general solution for cos(x)=0.12 is x=1.45050…+2pin,x=2pi-1.45050…+2pin