What is the general solution for 2cos(x)=3,0<= x<= 2pi ?

The general solution for 2cos(x)=3,0<= x<= 2pi is No Solution for x\in\mathbb{R}

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2cos(x)=3,0<= x<= 2pi

2 cos (x) = 3, 0 \leq x \leq 2 π

No Solution for x \in R

Solution steps

2 cos (x) = 3, 0 \leq x \leq 2 π

Divide both sides by

2

2 cos (x) = 3

Divide both sides by

2

\frac{2 cos ( x )}{2} = \frac{3}{2}

Simplify

cos (x) = \frac{3}{2}

cos (x) = \frac{3}{2}

- 1 \leq cos (x) \leq 1

No Solution for x \in R

7 sin (θ) = 5

tan (2 x) = 3, 0 \leq x \leq 2 π

4 tan^{2} (θ) + tan (θ) = - 4 tan (θ) - 1

8 cos (c) + 6 = 3 cos (c) + 7

2 csc (A) - 4 = 0

What is the general solution for 2cos(x)=3,0<= x<= 2pi ?
The general solution for 2cos(x)=3,0<= x<= 2pi is No Solution for x\in\mathbb{R}