What is the general solution for cos(θ)= 8/17 ,270<θ<360 ?

The general solution for cos(θ)= 8/17 ,270<θ<360 is θ=360-1.08083…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)= 8/17 ,270<θ<360

cos (θ) = \frac{8}{17}, 27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - 1.08083 \dots

Radians

θ = 2 π - 1.08083 \dots

Solution steps

cos (θ) = \frac{8}{17}, 27 0^{\circ} < θ < 36 0^{\circ}

Apply trig inverse properties

cos (θ) = \frac{8}{17}

General solutions for

cos (θ) = \frac{8}{17}

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (\frac{8}{17}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{8}{17}) + 36 0^{\circ} n

θ = arccos (\frac{8}{17}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{8}{17}) + 36 0^{\circ} n

Solutions for the range

27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - arccos (\frac{8}{17})

Show solutions in decimal form

θ = 36 0^{\circ} - 1.08083 \dots

2 csc (θ) - 3 = 0

cos (x - \frac{π}{7}) = \frac{- 2}{2}, 0 \leq x \leq 2 π

sin (2 θ) = sin (θ)

25 cos^{2} (θ) - 1 = 0

cos (θ) = \frac{4}{7}

What is the general solution for cos(θ)= 8/17 ,270<θ<360 ?
The general solution for cos(θ)= 8/17 ,270<θ<360 is θ=360-1.08083…