What is 4\times (2+5\div (4+1)-(3\div 3)\times 2)+6 ?

The solution to 4\times (2+5\div (4+1)-(3\div 3)\times 2)+6 is 10

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4\times (2+5\div (4+1)-(3\div 3)\times 2)+6

4 \times (2 + 5 \div (4 + 1) - (3 \div 3) \times 2) + 6

10

Solution steps

4 \times (2 + 5 \div (4 + 1) - (3 \div 3) \times 2) + 6

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 5 \div (4 + 1) - (3 \div 3) \times 2) : 1

2 + 5 \div (4 + 1) - (3 \div 3) \times 2

Calculate within parentheses

(4 + 1) : 5

4 + 1

4 + 1 = 5

= 5

= 2 + 5 \div 5 - (3 \div 3) \times 2

Calculate within parentheses

(3 \div 3) : 1

3 \div 3

3 \div 3 = 1

= 1

= 2 + 5 \div 5 - 1 \times 2

Multiply and divide (left to right)

5 \div 5 : 1

5 \div 5

5 \div 5 = 1

= 1

= 2 + 1 - 1 \times 2

Multiply and divide (left to right)

1 \times 2 : 2

1 \times 2

1 \times 2 = 2

= 2

= 2 + 1 - 2

Add and subtract (left to right)

2 + 1 - 2 : 1

2 + 1 - 2

2 + 1 = 3

= 3 - 2

3 - 2 = 1

= 1

= 1

= 4 \times 1 + 6

Multiply and divide (left to right)

4 \times 1 : 4

4 \times 1

4 \times 1 = 4

= 4

= 4 + 6

Add and subtract (left to right)

4 + 6 : 10

4 + 6

4 + 6 = 10

= 10

= 10

2 \frac{5}{2} + 2 - \frac{8}{7} + 6

50 - 4 \times 6 + 3 \times 5 - 9 \div 3

6 \times 4 \div 12 + 72 \div 8 - 9

(1 \div 8) + (5 \div 9)

(3 + 2)^{2} + [3 (4 - 6)^{2}]

What is 4\times (2+5\div (4+1)-(3\div 3)\times 2)+6 ?
The solution to 4\times (2+5\div (4+1)-(3\div 3)\times 2)+6 is 10