What is 4(1)^2-10(1)+12 ?

The solution to 4(1)^2-10(1)+12 is 6

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4(1)^2-10(1)+12

4 (1)^{2} - 10 (1) + 12

6

Solution steps

4 (1)^{2} - 10 (1) + 12

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 4 \cdot 1 - 10 (1) + 12

Multiply and divide (left to right)

4 \cdot 1 : 4

4 \cdot 1

4 \cdot 1 = 4

= 4

= 4 - 10 (1) + 12

Multiply and divide (left to right)

10 (1) : 10

10 (1)

Apply rule:

(a) = a

(1) = 1

= 10 \cdot 1

Multiply the numbers:

10 \cdot 1 = 10

= 10

= 4 - 10 + 12

Add and subtract (left to right)

4 - 10 + 12 : 6

4 - 10 + 12

4 - 10 = - 6

= - 6 + 12

- 6 + 12 = 6

= 6

= 6

\frac{2 ^{3} + 3 ^{2} + 1}{2 ^{2} + 5}

3^{1} - 4

3^{1} - 1

(1 1^{2} - 11 - 29) \div (11 - 6)

3 \frac{1}{3} - (- 2) \frac{4}{9}