What is 5(1/5-5)-25 ?

The solution to 5(1/5-5)-25 is -49

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5(1/5-5)-25

5 (\frac{1}{5} - 5) - 25

- 49

Solution steps

5 (\frac{1}{5} - 5) - 25

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{1}{5} - 5) : - \frac{24}{5}

\frac{1}{5} - 5

\frac{1}{5} - 5 = - \frac{24}{5}

\frac{1}{5} - 5

Convert element to fraction:

5 = \frac{5 \cdot 5}{5}

= - \frac{5 \cdot 5}{5} + \frac{1}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 5 \cdot 5 + 1}{5}

- 5 \cdot 5 + 1 = - 24

- 5 \cdot 5 + 1

Multiply the numbers:

5 \cdot 5 = 25

= - 25 + 1

Add/Subtract the numbers:

- 25 + 1 = - 24

= - 24

= \frac{- 24}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{24}{5}

= - \frac{24}{5}

= 5 (- \frac{24}{5}) - 25

Multiply and divide (left to right)

5 (- \frac{24}{5}) : - 24

5 (- \frac{24}{5})

Apply rule

a \cdot (- b) = - a \cdot b

5 (- \frac{24}{5}) = - 5 \cdot \frac{24}{5}

Convert element to fraction:

5 = \frac{5}{1}

= - \frac{5}{1} \cdot \frac{24}{5}

Cross-cancel common factor:

5

= - \frac{24}{1}

Divide the numbers:

\frac{24}{1} = 24

= - 24

= - 24 - 25

Add and subtract (left to right)

- 24 - 25 : - 49

- 24 - 25

- 24 - 25 = - 49

= - 49

= - 49

3 (1)^{2} - 18 (1) + 24

1 0^{2} + 2 0^{2}

\frac{( - 6 ) ( + 2 ) + ( - 4 - 3 ) + 1}{( - 8 + 10 ) + 7}

3 (4)^{4}

\frac{1}{2} (2)^{3}