What is ((-6)(+2)+(-4-3)+1)/((-8+10)+7) ?

The solution to ((-6)(+2)+(-4-3)+1)/((-8+10)+7) is -2

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((-6)(+2)+(-4-3)+1)/((-8+10)+7)

\frac{( - 6 ) ( + 2 ) + ( - 4 - 3 ) + 1}{( - 8 + 10 ) + 7}

- 2

Solution steps

\frac{( - 6 ) ( 2 ) + ( - 4 - 3 ) + 1}{( - 8 + 10 ) + 7}

Solve

(- 6) (2) + (- 4 - 3) + 1 : - 18

Follow the PEMDAS order of operations

Calculate within parentheses

(- 4 - 3) : - 7

- 4 - 3

- 4 - 3 = - 7

= - 7

= (- 6) (2) - 7 + 1

Multiply and divide (left to right)

(- 6) (2) : - 12

(- 6) (2)

Apply rule

(- a) \cdot (b) = - a \cdot b

(- 6) (2) = - 6 \cdot 2 = - 12

= - 12

= - 12 - 7 + 1

Add and subtract (left to right)

- 12 - 7 + 1 : - 18

- 12 - 7 + 1

- 12 - 7 = - 19

= - 19 + 1

- 19 + 1 = - 18

= - 18

= - 18

Solve

(- 8 + 10) + 7 : 9

Follow the PEMDAS order of operations

Calculate within parentheses

(- 8 + 10) : 2

- 8 + 10

- 8 + 10 = 2

= 2

= 2 + 7

Add and subtract (left to right)

2 + 7 : 9

2 + 7

2 + 7 = 9

= 9

= 9

= \frac{- 18}{9}

Simplify

\frac{- 18}{9} : - 2

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{18}{9}

Divide the numbers:

\frac{18}{9} = 2

= - 2

= - 2

3 (4)^{4}

\frac{1}{2} (2)^{3}

2 \cdot 3^{3} \div 9

- 2 - \frac{1}{4} (- \frac{4}{5})

18 \div 9 + 2 \cdot 6

What is ((-6)(+2)+(-4-3)+1)/((-8+10)+7) ?
The solution to ((-6)(+2)+(-4-3)+1)/((-8+10)+7) is -2