What is +2(-3)2-9-5+2(-3)^2 ?

The solution to +2(-3)2-9-5+2(-3)^2 is -8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

+2(-3)2-9-5+2(-3)^2

+ 2 (- 3) 2 - 9 - 5 + 2 (- 3)^{2}

- 8

Solution steps

2 (- 3) \cdot 2 - 9 - 5 + 2 (- 3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 2 (- 3) \cdot 2 - 9 - 5 + 2 \cdot 9

Multiply and divide (left to right)

2 (- 3) \cdot 2 : - 12

2 (- 3) \cdot 2

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 3) = - 2 \cdot 3 = - 6

= - 6 \cdot 2

- 6 \cdot 2 = - 12

= - 12

= - 12 - 9 - 5 + 2 \cdot 9

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= - 12 - 9 - 5 + 18

Add and subtract (left to right)

- 12 - 9 - 5 + 18 : - 8

- 12 - 9 - 5 + 18

- 12 - 9 = - 21

= - 21 - 5 + 18

- 21 - 5 = - 26

= - 26 + 18

- 26 + 18 = - 8

= - 8

= - 8

\frac{1}{5} (\frac{2}{3} - \frac{3}{5})

\frac{3}{2} (4^{3} - 2^{2} \cdot 3^{2})

6 \times 3 - 12 - 2 + 7 - 4 \times 3

\frac{- 1}{2} - 5 \times \frac{- 3}{4}

\frac{1}{4} (2) - 2