The solution to 1+3/5-5 is -17/5

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1+3/5-5

Solution

1 + \frac{3}{5} - 5

- \frac{17}{5}

Solution steps

1 + \frac{3}{5} - 5

Follow the PEMDAS order of operations

Add and subtract (left to right)

1 + \frac{3}{5} = \frac{8}{5}

1 + \frac{3}{5}

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} + \frac{3}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 + 3}{5}

1 \cdot 5 + 3 = 8

1 \cdot 5 + 3

Multiply the numbers:

1 \cdot 5 = 5

= 5 + 3

Add the numbers:

5 + 3 = 8

= 8

= \frac{8}{5}

= \frac{8}{5} - 5

\frac{8}{5} - 5 = - \frac{17}{5}

\frac{8}{5} - 5

Convert element to fraction:

5 = \frac{5 \cdot 5}{5}

= - \frac{5 \cdot 5}{5} + \frac{8}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 5 \cdot 5 + 8}{5}

- 5 \cdot 5 + 8 = - 17

- 5 \cdot 5 + 8

Multiply the numbers:

5 \cdot 5 = 25

= - 25 + 8

Add/Subtract the numbers:

- 25 + 8 = - 17

= - 17

= \frac{- 17}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{17}{5}

= - \frac{17}{5}

(2^{3} - 2) \div 3

\frac{176}{3} + 9 - \frac{264}{3}

19 - [2 \cdot (8 - (29 - 3 \cdot 2^{3})) - 4]

3 + (4^{3} \div 2) \times 5 - 17

3^{3} + 4^{4} + 3^{3} + 5^{5}