What is (-3)^4-2^4+(-1)^{15}+(-4)^3 ?

The solution to (-3)^4-2^4+(-1)^{15}+(-4)^3 is 0

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(-3)^4-2^4+(-1)^{15}+(-4)^3

(- 3)^{4} - 2^{4} + (- 1)^{15} + (- 4)^{3}

0

Solution steps

(- 3)^{4} - 2^{4} + (- 1)^{15} + (- 4)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{4} : 81

(- 3)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{4} = 3^{4} = 81

= 81

= 81 - 2^{4} + (- 1)^{15} + (- 4)^{3}

Calculate exponents

2^{4} : 16

2^{4}

2^{4} = 16

= 16

= 81 - 16 + (- 1)^{15} + (- 4)^{3}

Calculate exponents

(- 1)^{15} : - 1

(- 1)^{15}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{15} = - 1^{15} = - 1

= - 1

= 81 - 16 - 1 + (- 4)^{3}

Calculate exponents

(- 4)^{3} : - 64

(- 4)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 4)^{3} = - 4^{3} = - 64

= - 64

= 81 - 16 - 1 + (- 4)^{3}

Add and subtract (left to right)

81 - 16 - 1 + (- 4)^{3} : 0

81 - 16 - 1 + (- 4)^{3}

81 - 16 = 65

= 65 - 1 + (- 4)^{3}

65 - 1 = 64

= 64 + (- 4)^{3}

64 + (- 4)^{3} = 0

= 0

= 0

- 6^{2} - 9 (- 6) - 5

(- 4)^{2} - 4 (- 2) (- 2)

\frac{- 45 + 3 \times 5}{- 15}

2 (2)^{2} - 8 (2) - 4

85 - (\frac{2}{3} \times 65)

What is (-3)^4-2^4+(-1)^{15}+(-4)^3 ?
The solution to (-3)^4-2^4+(-1)^{15}+(-4)^3 is 0