What is (-4)^2-4(-2)(-2) ?

The solution to (-4)^2-4(-2)(-2) is 0

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(-4)^2-4(-2)(-2)

(- 4)^{2} - 4 (- 2) (- 2)

0

Solution steps

(- 4)^{2} - 4 (- 2) (- 2)

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 - 4 (- 2) (- 2)

Multiply and divide (left to right)

4 (- 2) (- 2) : 16

4 (- 2) (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 2) = - 4 \cdot 2 = - 8

= - 8 (- 2)

Apply rule

(- a) \cdot (- b) = a \cdot b

(- 8) (- 2) = 8 \cdot 2 = 16

= 16

= 16 - 16

Add and subtract (left to right)

16 - 16 : 0

16 - 16

16 - 16 = 0

= 0

= 0

\frac{- 45 + 3 \times 5}{- 15}

2 (2)^{2} - 8 (2) - 4

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