What is 2(3)^2-4(3)+7 ?

The solution to 2(3)^2-4(3)+7 is 13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2(3)^2-4(3)+7

2 (3)^{2} - 4 (3) + 7

13

Solution steps

2 (3)^{2} - 4 (3) + 7

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 2 \cdot 9 - 4 (3) + 7

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= 18 - 4 (3) + 7

Multiply and divide (left to right)

4 (3) : 12

4 (3)

Apply rule:

(a) = a

(3) = 3

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= 18 - 12 + 7

Add and subtract (left to right)

18 - 12 + 7 : 13

18 - 12 + 7

18 - 12 = 6

= 6 + 7

6 + 7 = 13

= 13

= 13

10 \div 2 + 4 - 3 + 8 \times 4 - 3 - 7 - 6 + 4 - 3 \div 2

2 - 5^{2}

50 \div 5 + 2 (2^{3} - 2^{2})

(8 \times (- 3))^{2} + (9 \times + 1^{2})

- 3 - [(- 1 + 6) + 4 - (- 1 - 2) - 1]