What is -2(1)^2+8(1)-5 ?

The solution to -2(1)^2+8(1)-5 is 1

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-2(1)^2+8(1)-5

- 2 (1)^{2} + 8 (1) - 5

1

Solution steps

- 2 (1)^{2} + 8 (1) - 5

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= - 2 \cdot 1 + 8 (1) - 5

Multiply and divide (left to right)

- 2 \cdot 1 : - 2

- 2 \cdot 1

- 2 \cdot 1 = - 2

= - 2

= - 2 + 8 (1) - 5

Multiply and divide (left to right)

8 (1) : 8

8 (1)

Apply rule:

(a) = a

(1) = 1

= 8 \cdot 1

Multiply the numbers:

8 \cdot 1 = 8

= 8

= - 2 + 8 - 5

Add and subtract (left to right)

- 2 + 8 - 5 : 1

- 2 + 8 - 5

- 2 + 8 = 6

= 6 - 5

6 - 5 = 1

= 1

= 1

- 2^{2} - 2 \cdot (- 2) - 3

\frac{3 ^{2} + 8}{3 ^{3} - 25 ( 3 )}

\frac{1}{2} \times 2 - 3

\frac{1}{2} \times 2 - 1

23 + (- 10) + 13