What is (3^2+8)/(3^3-25(3)) ?

The solution to (3^2+8)/(3^3-25(3)) is -17/48

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(3^2+8)/(3^3-25(3))

\frac{3 ^{2} + 8}{3 ^{3} - 25 ( 3 )}

- \frac{17}{48}

Solution steps

\frac{3 ^{2} + 8}{3 ^{3} - 25 ( 3 )}

Solve

3^{2} + 8 : 17

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 + 8

Add and subtract (left to right)

9 + 8 : 17

9 + 8

9 + 8 = 17

= 17

= 17

Solve

3^{3} - 25 (3) : - 48

Follow the PEMDAS order of operations

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= 27 - 25 (3)

Multiply and divide (left to right)

25 (3) : 75

25 (3)

Apply rule:

(a) = a

(3) = 3

= 25 \cdot 3

Multiply the numbers:

25 \cdot 3 = 75

= 75

= 27 - 75

Add and subtract (left to right)

27 - 75 : - 48

27 - 75

27 - 75 = - 48

= - 48

= - 48

= \frac{17}{- 48}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{17}{48}

\frac{1}{2} \times 2 - 3

\frac{1}{2} \times 2 - 1

23 + (- 10) + 13

- 2 [0 \div (10 \div 2)]

3 + 12 + 6^{3}