What is (8+1/3 \times 64)-(6+9) ?

The solution to (8+1/3 \times 64)-(6+9) is 14 1/3

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Popular >

(8+1/3 \times 64)-(6+9)

Solution

(8 + \frac{1}{3} \cdot 64) - (6 + 9)

Solution

14 \frac{1}{3}

Solution steps

(8 + \frac{1}{3} \cdot 64) - (6 + 9)

Follow the PEMDAS order of operations

Calculate within parentheses

(8 + \frac{1}{3} \cdot 64) : \frac{88}{3}

8 + \frac{1}{3} \cdot 64

Multiply and divide (left to right)

\frac{1}{3} \cdot 64 : \frac{64}{3}

\frac{1}{3} \cdot 64

Convert element to fraction:

64 = \frac{64}{1}

= \frac{1}{3} \cdot \frac{64}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 64}{3 \cdot 1}

Multiply the numbers:

1 \cdot 64 = 64

= \frac{64}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{64}{3}

= 8 + \frac{64}{3}

Add and subtract (left to right)

8 + \frac{64}{3} : \frac{88}{3}

8 + \frac{64}{3}

8 + \frac{64}{3} = \frac{88}{3}

8 + \frac{64}{3}

Convert element to fraction:

8 = \frac{8 \cdot 3}{3}

= \frac{8 \cdot 3}{3} + \frac{64}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{8 \cdot 3 + 64}{3}

8 \cdot 3 + 64 = 88

8 \cdot 3 + 64

Multiply the numbers:

8 \cdot 3 = 24

= 24 + 64

Add the numbers:

24 + 64 = 88

= 88

= \frac{88}{3}

= \frac{88}{3}

= \frac{88}{3}

= \frac{88}{3} - (6 + 9)

Calculate within parentheses

(6 + 9) : 15

6 + 9

6 + 9 = 15

= 15

= \frac{88}{3} - 15

Add and subtract (left to right)

\frac{88}{3} - 15 : \frac{43}{3}

\frac{88}{3} - 15

\frac{88}{3} - 15 = \frac{43}{3}

\frac{88}{3} - 15

Convert element to fraction:

15 = \frac{15 \cdot 3}{3}

= - \frac{15 \cdot 3}{3} + \frac{88}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 15 \cdot 3 + 88}{3}

- 15 \cdot 3 + 88 = 43

- 15 \cdot 3 + 88

Multiply the numbers:

15 \cdot 3 = 45

= - 45 + 88

Add/Subtract the numbers:

- 45 + 88 = 43

= 43

= \frac{43}{3}

= \frac{43}{3}

= \frac{43}{3}

Convert improper fractions to mixed numbers:

\frac{43}{3} = 14 \frac{1}{3}

\frac{43}{3} = 14

Remainder

1

\frac{43}{3}

Write the problem in long division format

3 \overline{∣ 43}

Divide

4

3

to get

1

Divide

4

3

to get

1

1 3 \overline{∣ 43}

Multiply the quotient digit

(1)

by the divisor

3

1 3 \overline{∣ 43} \underline{3}

Subtract

3

from

4

1 3 \overline{∣ 43} \underline{3} 1

Bring down the next number of the dividend

1 3 \overline{∣ 43} \underline{3} 13

1 3 \overline{∣ 43} \underline{3} 13

Divide

13

3

to get

4

Divide

13

3

to get

4

14 3 \overline{∣ 43} \underline{3} 13

Multiply the quotient digit

(4)

by the divisor

3

14 3 \overline{∣ 43} \underline{3} 13 \underline{12}

Subtract

12

from

13

14 3 \overline{∣ 43} \underline{3} 13 \underline{12} 1

14 3 \overline{∣ 43} \underline{3} 13 \underline{12} 1

The solution for Long Division of

\frac{43}{3}

14

with remainder of

1

14 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{43}{3} = 14 \frac{1}{3}

= 14 \frac{1}{3}

= 14 \frac{1}{3}

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17 - 2^{2} + 8

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4^3\div ((28-3^3)+121\div 11^2)^3

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Frequently Asked Questions (FAQ)

What is (8+1/3 \times 64)-(6+9) ?
The solution to (8+1/3 \times 64)-(6+9) is 14 1/3