What is 2*(-1)-1/5*1+7*(-1)-3 ?

The solution to 2*(-1)-1/5*1+7*(-1)-3 is -61/5

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2(-1)-1/51+7*(-1)-3

2 \cdot (- 1) - \frac{1}{5} \cdot 1 + 7 \cdot (- 1) - 3

- \frac{61}{5}

Solution steps

2 (- 1) - \frac{1}{5} \cdot 1 + 7 (- 1) - 3

Follow the PEMDAS order of operations

Multiply and divide (left to right)

2 (- 1) : - 2

2 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 1) = - 2 \cdot 1 = - 2

= - 2

= - 2 - \frac{1}{5} \cdot 1 + 7 (- 1) - 3

Multiply and divide (left to right)

\frac{1}{5} \cdot 1 : \frac{1}{5}

\frac{1}{5} \cdot 1

\frac{1}{5} \cdot 1 = \frac{1}{5}

= \frac{1}{5}

= - 2 - \frac{1}{5} + 7 (- 1) - 3

Multiply and divide (left to right)

7 (- 1) : - 7

7 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

7 (- 1) = - 7 \cdot 1 = - 7

= - 7

= - 2 - \frac{1}{5} - 7 - 3

Add and subtract (left to right)

- 2 - \frac{1}{5} - 7 - 3 : - \frac{61}{5}

- 2 - \frac{1}{5} - 7 - 3

- 2 - \frac{1}{5} = - \frac{11}{5}

= - \frac{11}{5} - 7 - 3

- \frac{11}{5} - 7 = - \frac{46}{5}

- \frac{11}{5} - 7

Convert element to fraction:

7 = \frac{7 \cdot 5}{5}

= - \frac{7 \cdot 5}{5} - \frac{11}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 7 \cdot 5 - 11}{5}

- 7 \cdot 5 - 11 = - 46

- 7 \cdot 5 - 11

Multiply the numbers:

7 \cdot 5 = 35

= - 35 - 11

Subtract the numbers:

- 35 - 11 = - 46

= - 46

= \frac{- 46}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{46}{5}

= - \frac{46}{5} - 3

- \frac{46}{5} - 3 = - \frac{61}{5}

- \frac{46}{5} - 3

Convert element to fraction:

3 = \frac{3 \cdot 5}{5}

= - \frac{3 \cdot 5}{5} - \frac{46}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 5 - 46}{5}

- 3 \cdot 5 - 46 = - 61

- 3 \cdot 5 - 46

Multiply the numbers:

3 \cdot 5 = 15

= - 15 - 46

Subtract the numbers:

- 15 - 46 = - 61

= - 61

= \frac{- 61}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{61}{5}

= - \frac{61}{5}

= - \frac{61}{5}

1 - 5^{2}

3 - (\frac{1}{5} + \frac{5}{3})

3 (2)^{4}

3 (2)^{0}

4 0^{2} + 3 0^{2}