What is (-2)^2-(-4)^2+8(-3)-25 ?

The solution to (-2)^2-(-4)^2+8(-3)-25 is -61

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(-2)^2-(-4)^2+8(-3)-25

(- 2)^{2} - (- 4)^{2} + 8 (- 3) - 25

- 61

Solution steps

(- 2)^{2} - (- 4)^{2} + 8 (- 3) - 25

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 - (- 4)^{2} + 8 (- 3) - 25

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 4 - 16 + 8 (- 3) - 25

Multiply and divide (left to right)

8 (- 3) : - 24

8 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

8 (- 3) = - 8 \cdot 3 = - 24

= - 24

= 4 - 16 - 24 - 25

Add and subtract (left to right)

4 - 16 - 24 - 25 : - 61

4 - 16 - 24 - 25

4 - 16 = - 12

= - 12 - 24 - 25

- 12 - 24 = - 36

= - 36 - 25

- 36 - 25 = - 61

= - 61

= - 61

- 8 - 30 (- 12) - 7

12 - [7 - (2 - 10)]

- 3 + 5 - 2 + 3 + 7

(- 2)^{2} + 2 (- 2) + 4

108 \div 360 \times 6^{2}