What is (-2)^2+2(-2)+4 ?

The solution to (-2)^2+2(-2)+4 is 4

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(-2)^2+2(-2)+4

(- 2)^{2} + 2 (- 2) + 4

4

Solution steps

(- 2)^{2} + 2 (- 2) + 4

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 2 (- 2) + 4

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= 4 - 4 + 4

Add and subtract (left to right)

4 - 4 + 4 : 4

4 - 4 + 4

4 - 4 = 0

= 0 + 4

0 + 4 = 4

= 4

= 4

108 \div 360 \times 6^{2}

5^{2} - 21

5^{2} + 3^{2} + 1^{2}

3^{3} - 2^{4}

3 \times 4 + 6