What is 4-(-4)^2+(-3-3)^2 ?

The solution to 4-(-4)^2+(-3-3)^2 is 24

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4-(-4)^2+(-3-3)^2

4 - (- 4)^{2} + (- 3 - 3)^{2}

24

Solution steps

4 - (- 4)^{2} + (- 3 - 3)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(- 3 - 3) : - 6

- 3 - 3

- 3 - 3 = - 6

= - 6

= 4 - (- 4)^{2} + (- 6)^{2}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 4 - 16 + (- 6)^{2}

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= 4 - 16 + 36

Add and subtract (left to right)

4 - 16 + 36 : 24

4 - 16 + 36

4 - 16 = - 12

= - 12 + 36

- 12 + 36 = 24

= 24

= 24

\frac{85000}{( 13% - 6% ) - 1400000}

5 + 4 \times 6 - 18 \div 3 + 1

5 \cdot 4^{2} - 8 \cdot 2 + 5

(5 - 7) (5 - 6)

(+ 6) + (- 5) + (+ 3) + (- 2)