What is (-2-1)^2(-2+2) ?

The solution to (-2-1)^2(-2+2) is 0

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(-2-1)^2(-2+2)

(- 2 - 1)^{2} (- 2 + 2)

0

Solution steps

(- 2 - 1)^{2} (- 2 + 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 2 - 1) : - 3

- 2 - 1

- 2 - 1 = - 3

= - 3

= (- 3)^{2} (- 2 + 2)

Calculate within parentheses

(- 2 + 2) : 0

- 2 + 2

- 2 + 2 = 0

= 0

= (- 3)^{2} \cdot 0

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 \cdot 0

Multiply and divide (left to right)

9 \cdot 0 : 0

9 \cdot 0

9 \cdot 0 = 0

= 0

= 0

3 (3)^{2} - 2

(\frac{2}{5} \cdot \frac{3}{10}) \cdot 5

7 (3) - 2 (4)

5^{2} - 7^{2} + 9^{2} - 1 1^{2} + 1 3^{2} - 1 5^{2}

1^{2} + 2 + 3^{2}