What is 16/3 (-1)-79/3 ?

The solution to 16/3 (-1)-79/3 is -95/3

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16/3 (-1)-79/3

\frac{16}{3} (- 1) - \frac{79}{3}

- \frac{95}{3}

Solution steps

\frac{16}{3} (- 1) - \frac{79}{3}

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{16}{3} (- 1) : - \frac{16}{3}

\frac{16}{3} (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{16}{3} (- 1) = - \frac{16}{3} \cdot 1 = - \frac{16}{3}

= - \frac{16}{3}

= - \frac{16}{3} - \frac{79}{3}

Add and subtract (left to right)

- \frac{16}{3} - \frac{79}{3} : - \frac{95}{3}

- \frac{16}{3} - \frac{79}{3}

- \frac{16}{3} - \frac{79}{3} = - \frac{95}{3}

- \frac{16}{3} - \frac{79}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 16 - 79}{3}

Subtract the numbers:

- 16 - 79 = - 95

= \frac{- 95}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{95}{3}

= - \frac{95}{3}

= - \frac{95}{3}

+ 4 \times 5 - (28 \div 2) \div 2 + 16

\frac{3 ( - 2 ) ( 3 ) - 2 ( - 1 ) ( 2 )}{4 ( - 2 ) ( - 1 )}

- 2 (- 4) + 1

8 - 6 \times 0

5 \div 1 \div 2