What is (2)^3+9\times (2)^2-34\times (2)+24 ?

The solution to (2)^3+9\times (2)^2-34\times (2)+24 is 0

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(2)^3+9\times (2)^2-34\times (2)+24

(2)^{3} + 9 \cdot (2)^{2} - 34 \cdot (2) + 24

0

Solution steps

(2)^{3} + 9 (2)^{2} - 34 (2) + 24

Follow the PEMDAS order of operations

Calculate exponents

(2)^{3} : 8

(2)^{3}

(2)^{3} = 8

= 8

= 8 + 9 (2)^{2} - 34 (2) + 24

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 8 + 9 \cdot 4 - 34 (2) + 24

Multiply and divide (left to right)

9 \cdot 4 : 36

9 \cdot 4

9 \cdot 4 = 36

= 36

= 8 + 36 - 34 (2) + 24

Multiply and divide (left to right)

34 (2) : 68

34 (2)

Apply rule:

(a) = a

(2) = 2

= 34 \cdot 2

Multiply the numbers:

34 \cdot 2 = 68

= 68

= 8 + 36 - 68 + 24

Add and subtract (left to right)

8 + 36 - 68 + 24 : 0

8 + 36 - 68 + 24

8 + 36 = 44

= 44 - 68 + 24

44 - 68 = - 24

= - 24 + 24

- 24 + 24 = 0

= 0

= 0

(- 2)^{2} - (- 2) - 6

3 (- 2)^{2} + 12 (- 2) + 9

3 \cdot 24 - 5 \cdot 4^{2} - 217 \div 7

4 - 2 {3 [5 - 2 (5 - 6) - 7] + 10} + 17

(+ 35)^{0} + (- 6) \div (- 6) + 2^{3}

What is (2)^3+9\times (2)^2-34\times (2)+24 ?
The solution to (2)^3+9\times (2)^2-34\times (2)+24 is 0