What is (3)^2-10(3)+16 ?

The solution to (3)^2-10(3)+16 is -5

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(3)^2-10(3)+16

(3)^{2} - 10 (3) + 16

- 5

Solution steps

(3)^{2} - 10 (3) + 16

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 9 - 10 (3) + 16

Multiply and divide (left to right)

10 (3) : 30

10 (3)

Apply rule:

(a) = a

(3) = 3

= 10 \cdot 3

Multiply the numbers:

10 \cdot 3 = 30

= 30

= 9 - 30 + 16

Add and subtract (left to right)

9 - 30 + 16 : - 5

9 - 30 + 16

9 - 30 = - 21

= - 21 + 16

- 21 + 16 = - 5

= - 5

= - 5

- 7 \times (6 - 7) + 8 \times (7 - 9)

- 6 + (- 5) - 7 - (- 9 + 11)

\frac{4}{2 ( 5 + 5 )}

\frac{( - 6 ) ^{2} + ( - 6 ) - 6}{( - 6 ) ^{2} + 2 ( - 6 ) - 8}

\frac{7 ^{2} - 13}{24 - 18}