What is -180(1-20/50) ?

The solution to -180(1-20/50) is -108

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-180(1-20/50)

- 180 (1 - \frac{20}{50})

- 108

Solution steps

- 180 (1 - \frac{20}{50})

\frac{20}{50} = \frac{2}{5}

Cancel the common factor:

10

\frac{2}{5}

= - 180 (1 - \frac{2}{5})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{2}{5}) : \frac{3}{5}

1 - \frac{2}{5}

1 - \frac{2}{5} = \frac{3}{5}

1 - \frac{2}{5}

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} - \frac{2}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 - 2}{5}

1 \cdot 5 - 2 = 3

1 \cdot 5 - 2

Multiply the numbers:

1 \cdot 5 = 5

= 5 - 2

Subtract the numbers:

5 - 2 = 3

= 3

= \frac{3}{5}

= \frac{3}{5}

= - 180 \cdot \frac{3}{5}

Multiply and divide (left to right)

- 180 \cdot \frac{3}{5} : - 108

- 180 \cdot \frac{3}{5}

Convert element to fraction:

180 = \frac{180}{1}

= - \frac{180}{1} \cdot \frac{3}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{180}{1} \cdot \frac{3}{5} = \frac{180 \cdot 3}{1 \cdot 5}

= - \frac{180 \cdot 3}{1 \cdot 5}

Cancel

\frac{180 \cdot 3}{1 \cdot 5} : 108

\frac{180 \cdot 3}{1 \cdot 5}

Multiply the numbers:

1 \cdot 5 = 5

= \frac{180 \cdot 3}{5}

Divide the numbers:

\frac{180}{5} = 36

= 36 \cdot 3

Multiply the numbers:

36 \cdot 3 = 108

= 108

= - 108

= - 108

\frac{- 200 + 75}{- 3 + ( 2 ) ( 4 )}

14 - [2 \times (8 - (29 - 3 \times 2^{3})) - 4]

4 \times (2 \times (- 1))

(- 5) + (+ 3) + (+ 4) + (- 2)

\frac{4}{3} + (\frac{5}{6} + \frac{1}{2})